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barxatty [35]
3 years ago
7

Benefits of using n2o as a refrigerant.

Chemistry
1 answer:
Murrr4er [49]3 years ago
5 0
Mexican Texas<span> is the historiographical name used to refer to the era of </span>Texan<span> history between 1821 and 1836, </span>when it was part<span> of </span>Mexico<span>. </span>Mexico gained independence<span> from Spain in 1821 in </span>its war<span> of</span>independence<span>. Initially, </span>Mexican Texas<span> operated very similarly to Spanish </span>Texas<span>.</span>
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What parts are present in every chemical equation?
WITCHER [35]
The reactants, products, coefficients, subscripts. ( I forgot the rest lol)
5 0
2 years ago
Give explanations for the large drops in melting point from C to Si and from Ge to Sn.
____ [38]

As we move down the group, the metallic bond becomes more stable and the formation of forming covalent bond decreases down the group due to the large size of elements.

Covalent and metallic bonding leads to higher melting points. Due to a decrease in attractive forces from carbon to lead there is a drop in melting point.

Carbon forms large covalent molecules than silicon and hence has a higher melting point than silicon.

Similarly, Ge also forms a large number of covalent bonds and has a smaller size as compared to that of Sn. Hence melting point decreases from Ge to Sn.

The order will be C>Si>Ge>Pb>Sn.

To learn more about the covalent bond, visit: brainly.com/question/10777799

#SPJ4

3 0
1 year ago
Someone help me please!!!
Montano1993 [528]

A. 6 moles

B. 9 moles

C. 3 moles

D.  20 moles

I think please check me, in case I am wrong

8 0
3 years ago
A 31.1 g wafer of pure gold, initially at 69.3 _c, is submerged into 64.2 g of water at 27.8 _c in an insulated container. what
KIM [24]
Given:
Ma = 31.1 g, the mass of gold
Ta = 69.3 °C, the initial temperature of gold
Mw = 64.2 g, the mass of water
Tw = 27.8 °C, the initial temperature of water 

Because the container is insulated, no heat is lost to the surroundings.
Let T °C be the final temperature.

From tables, obtain
Ca = 0.129 J/(g-°C), the specific heat of gold
Cw = 4.18 J/(g-°C), the specific heat of water

At equilibrium, heat lost by the gold - heat gained by the water.
Heat lost by the gold is
Qa = Ma*Ca*(T - Ta)
      = (31.1 g)*(0.129 J/(g-°C)(*(69.3 - T °C)- 
      = 4.0119(69.3 - T) j
Heat gained by the water is
Qw = Mw*Cw*(T-Tw)
       = (64.2 g)*(4.18 J/(g-°C))*(T - 27.8 °C)
       = 268.356(T - 27.8)

Equate Qa and Qw.
268.356(T - 27.8) = 4.0119(69.3 - T)
272.3679T = 7738.32
T = 28.41 °C

Answer: 28.4 °C

3 0
3 years ago
Read 2 more answers
calculate the molality of commercial HCl solution which is 12.1Molarity, and has a density of 1.19g/mL, and is 37.2wt.%HCl.
shutvik [7]

Answer:

0.44165 Molal

8 0
3 years ago
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