Answer:
C. how the size of a magnet affects the strength of its magnetic pull on objects.
Explanation:
"Magnetic force" is <em>inversely proportional to distance squared. </em>This is also related to the size of a magnet. The bigger the size, the bigger the domain it occupies and the stronger the magnetic field. However, this is not often the case and it largely depends on the types of magnets.
In the situation above, Jazelle wanted to determine how her five different-sized magnet affect the strength of their magnetic pull on the paper clips. In order to do this, she tried to<em> measure the distance</em>. The<em> closer the distance</em>, the <em>higher the magnetic field</em> and the stronger the strength. The farther the distance, the<em> lower the magnetic field</em> and the <em>weaker the strength.</em>
So, this explains the answer.
Answer
Part A:
Given equation:
The above equation is an example of a double replacement reaction. A double replacement (or double displacement) reaction is a reaction in which the positive and negative ions of two ionic compounds exchange.
Note: The oxidation number of:
K = +1
I = -1
Ba = +2
S = -2
So, the complete chemical equation including phases of the given reaction is:
Part B:
Given equation:
Also, the equation is an example of a double replacement reaction.
Note: The oxidation number of:
K = +1
Cl = -1
Ca = +2
S = -2
The complete chemical equation including phases of the given reaction is:
Answer:
The answers to your question are below
Explanation:
a) 6.85×1020 H2O2 molecules
H2O2 MW = 32 + 2 = 34 g
34g -------------------- 6.023 x 10²³ molecules
x ------------------- 6.85 x 10 ²⁰
x = (6.85 x 10 ²⁰)(34)/ 6.023 x 10²³
x = 0.038 g
3.3×1022 SO2 molecules
MW SO2 = 32 + 32 = 64g
64 g -------------------- 6.023 x 10²³ molecules
x -------------------- 3.3×1022 SO2 molecules
x = (3.3×1022 SO2)(64) / 6.023 x 10²³
x = 3.51 g
5.5×1025 O3 molecules
MW = 16 x 3 = 48g
48 g ----------------- 6.023 x 10²³ molecules
x ------------------ 5.5×1025 O3 molecules
x = (5.5×1025 )(48) / 6.023 x 10²³
x = 4383 g
9.30×1019 CH4 molecules
MW = 12 + 4 = 16 g
16 g -------------------- 6.023 x 10²³ molecules
x -------------------- 9.30×1019 CH4 molecules
x = (9.30×1019)(16) / 6.023 x 10²³
x = 0.0025 g
