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Artyom0805 [142]
3 years ago
12

Where is the exact volume of the sphere

Mathematics
1 answer:
baherus [9]3 years ago
7 0

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12.3 \end{cases}\implies V=\cfrac{4\pi (12.3)^3}{3}\implies \stackrel{\pi =3.14}{V\approx 7790.83}

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12) The length of one side of a triangle is 24 cm and the length of its hypotenuse is 40 cm. find the length of its third side.​
ivanzaharov [21]

Answer:

32

Step-by-step explanation:

given the triangle is right triangle

c^2 = a^2 + b^2

40^2 = 24^2 + b^2

1600 = 576 + b^2

b^2 = 1024

b = 32

6 0
2 years ago
A school wants to buy a chalkboard that measures 3 feet by 4 feet the chalkboard cost $6.14 per square foot. How much will the c
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Answer:

$49.12

Step-by-step explanation:

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3 years ago
A circular cone has volume 1200 cubic inches and radius 5 inches. What is the height of the cone, to the nearest tenth inch?
asambeis [7]

I multiply 1200 times 5 and yet 6000 because it says what is the height

3 0
3 years ago
The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
2 years ago
Simplify:<br> 3x+1b+10g-4x
Aneli [31]

Answer:

b+10g-x

Step-by-step explanation:

3x-4x=x

New equation becomes:

b+10g-x

4 0
2 years ago
Read 2 more answers
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