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Artyom0805 [142]
3 years ago
12

Where is the exact volume of the sphere

Mathematics
1 answer:
baherus [9]3 years ago
7 0

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=12.3 \end{cases}\implies V=\cfrac{4\pi (12.3)^3}{3}\implies \stackrel{\pi =3.14}{V\approx 7790.83}

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Find the area of rectangle ABCD
satela [25.4K]

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Answer:

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Step-by-step explanation:

There are a number of ways to find the area of this rectangle. Perhaps the most straightforward is to find the lengths of the sides and multiply those. The distance formula is useful.

  d = √((x2 -x1)^2 +(y2 -y1)^2)

Using the two upper-left points, we find the length of that side to be ...

  d = √((3 -0)^2 +(3 -0)^2) = √(9 +9) = √18 = 3√2

Similarly, the length of the lower-left side is ...

  d = √((-2 -0)^2 +(-2 -0)^2) = √(4+4) = √8 = 2√2

Then the area of the rectangle is ...

  A = LW

  A = (3√2)(2√2) = 3·2·(√2)^2 = 3·2·2 = 12

The area of rectangle ABCD is 12.

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Other methods include subtracting the area of the corner triangles from the area of the bounding square:

  5^2 -2(1/2)(3·3) -2(1/2)(2·2) = 25 -9 -4 = 12

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Answer:

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Step-by-step explanation:

Given that

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It means that we have to find probability P(X>4).

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We know that

P(X=x)=(_{x}^{n})\ p^xq^{n-x}

P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009

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P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043

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P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

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3 years ago
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Answer:

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