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3 years ago

5

What is the y value of this minimum

1 answer:

kozerog [31]3 years ago

3 0

For this, we just need to solve the function when x = 4. So firstly, plug in 4 in the x variable.

$y=4^2-8(4)+12$

Next, solve the exponents and multiplications: $y=16-32+12$

Next, combine everything on the right side of the equation, and your answer will be y = -4

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BlackZzzverrR [31]

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