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zlopas [31]
3 years ago
5

HELP WITH 1-4 !!!!!

Mathematics
1 answer:
mariarad [96]3 years ago
8 0

1. Congruent

2. Similar

3. Similar

4. Congruent

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How to do this!!! Help me ASAP!!!!
BARSIC [14]

Answer:

idk either sorry but

Step-by-step explanation:

I think you need a protractor to help you find the other angles to find x

5 0
3 years ago
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
Match each graph with the correct slope of the line. drag and drop the answer
OLEGan [10]

Answer/Step-by-step explanation:

✔️Slope of the first graph:

Using two points on the line, (0, 1) and (3, 2),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 1}{3 - 0} = \frac{1}{3}

Slope = ⅓

✔️Slope of the second graph:

Using two points on the line, (0, 0) and (1, 1),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 0}{1 - 0} = \frac{1}{1} = 1

Slope = 1

✔️Slope of the third graph:

Using two points on the line, (0, 1) and (2, 2),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 1}{2 - 0} = \frac{1}{2}

Slope = ½

3 0
3 years ago
Read 2 more answers
Which of the following points is the greatest distance form y -axis a.2,7 b.3,5 c.4,3 d.5,1
ohaa [14]

Answer:

D

Step-by-step explanation:

It's d because it has the highest x value. The higher x value is the farther it is from the y-axis

7 0
3 years ago
What does this say? Please Help me!
kvasek [131]

Answer:

That is a child mom with triplets.

Step-by-step explanation:

7 0
3 years ago
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