Answer:
D (the last one)
Step-by-step explanation:
because the line on the outside of the numbers means they're absolute.
the absolute is how far they are from zero no matter if they are negative or positive.
Answer:
K= 2/3
Step-by-step explanation:
tell me if its right.
Answer:
4)Y axis :X=0
5)A:2units B:4 units C:7units D:7units
A':2units B':4units C':7units D':7units
6)They are correspondingly the same
7)A(2;1) B(4;4) C(7;4) D(7;1)
A'(-2;1) B'(-4;4) C'(-7;4) D(-7;1)
<span>We want to optimize f(x,y,z)=x^2 y^2 z^2, subject to g(x,y,z) = x^2 + y^2 + z^2 = 289.
Then, ∇f = λ∇g ==> <2xy^2 z^2, 2x^2 yz^2, 2x^2 y^2 z> = λ<2x, 2y, 2z>.
Equating like entries:
xy^2 z^2 = λx
x^2 yz^2 = λy
x^2 y^2 z = λz.
Hence, x^2 y^2 z^2 = λx^2 = λy^2 = λz^2.
(i) If λ = 0, then at least one of x, y, z is 0, and thus f(x,y,z) = 0 <---Minimum
(Note that there are infinitely many such points.)
(f being a perfect square implies that this has to be the minimum.)
(ii) Otherwise, we have x^2 = y^2 = z^2.
Substituting this into g yields 3x^2 = 289 ==> x = ±17/√3.
This yields eight critical points (all signage possibilities)
(x, y, z) = (±17/√3, ±17/√3, ±17/√3), and
f(±17/√3, ±17/√3, ±17/√3) = (289/3)^3 <----Maximum
I hope this helps! </span><span>
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