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dolphi86 [110]
2 years ago
8

Find an integer $x$ such that $\frac{2}{3} < \frac{x}{5} < \frac{6}{7}$.

Mathematics
2 answers:
julsineya [31]2 years ago
6 0

Answer:

5

Step-by-step explanation

Aops Question

alexandr1967 [171]2 years ago
5 0

Answer:

4

Step-by-step explanation:

It's AoPS question

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Can someone help me solve this alpine with an explanation thank u (will mark as brainlist if correct&amp;explanation)
Dahasolnce [82]

Answer:

(d). \frac{12}{5}

Step-by-step explanation:

7 0
1 year ago
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Find the equation of a circle whose endpoints of the diameter are (15, - 3) and (7,3). The equation of the circle is (Simplify y
Nana76 [90]

Answer:

(x - 11)² + y² = 25

Step-by-step explanation:

First find the center

O = ( (15 +7 / 2), (-3 + 3)/2 )

O = (11, 0)

Then find the radius squared

use the distance formula from the center to either end point of the diameter

r² = (15 - 11)² + (-3 - 0)²

r² = 16 + 9

r² = 25

Formula for circle

(x - h)² + (y - k)² = r²

(h, k) is the center = (11, 0)

The equation is

(x - 11)² + y² = 25

8 0
3 years ago
7 times what gives me 36
Zolol [24]
To get the answer, divide 36 by 7. And the answer of that is 5.1428571428571429
8 0
2 years ago
6x-5y=15 x=y+3 find x and y
arlik [135]

Answer:

(0, -3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

6x - 5y = 15

x = y + 3

<u>Step 2: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                                                                                                  6(y + 3) - 5y = 15
  2. Distribute 6:                                                                                                    6y + 18 - 5y = 15
  3. Combine like terms:                                                                                        y + 18 = 15
  4. [Subtraction Property of Equality] Subtract 18 on both sides:                     y = -3

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x = y + 3
  2. Substitute in <em>y</em>:                                                                                                   x = -3 + 3
  3. Add:                                                                                                                   x = 0
7 0
3 years ago
Judy is playing a card game. She needs to select two cards below that have a sum greater
Zielflug [23.3K]

Answer:

2\frac{2}{5}  + 2\frac{5}{8} \simeq 5

2\frac{2}{7}  + 2\frac{5}{8}  \simeq 5

Step-by-step explanation:

Mixed fraction a\frac{b}{c} can be converted into like or unlike fractions.

Here, a\frac{b}{c} =  \frac{ac +b}{b}

So, convert all the given fractions as follows:

2\frac{2}{5} =  \frac{2(5) +2}{5} = \frac{12}{5}  =2.4

2\frac{2}{7} =  \frac{2(7) +2}{7} = \frac{16}{7}  =2.4

1\frac{7}{8} =  \frac{1(8) +7}{8} = \frac{15}{8}  =1.8

2\frac{1}{10} =  \frac{2(10) + 1}{10} = \frac{21}{10}  =2.1

2\frac{5}{8} =  \frac{2(8) +5}{8} = \frac{21}{8}  =2.6

Here, No Two fractions on addition gives a sum greater than 5.

But an approximate sum of 5 is given by adding 2.4 + 2.6 = 5

⇒2\frac{2}{5}  + 2\frac{5}{8} \simeq 5

or  ⇒2\frac{2}{7}  + 2\frac{5}{8}  \simeq 5

7 0
3 years ago
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