Answer:
Step-by-step explanation:
![\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%3D%20%5Cfrac%7Bx%5E2%28y-2%29%7D%7B3y%7D%20%5C%5C%5C%5CPut%20%5C%20x%20%3D%203%2C%20%5C%20y%20%3D%20-1%5C%5C%5C%5C%3D%20%5Cfrac%7B%283%29%5E2%28-1-2%29%7D%7B3%28-1%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B9%28-3%29%7D%7B-3%7D%20%5C%5C%5C%5C%3D%209%20%5C%5C%5C%5C%20%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
Answer: Choice D. y = (x-1)^2 - 3
The vertex is (h,k) = (1,-3). So h = 1 and k = -3.
We have a = 1 as the leading coefficient.
Plug those values into the equation below
y = a(x-h)^2 + k
y = 1(x - 1)^2 + (-3)
y = (x - 1)^2 - 3
Y+x=98
y-x=22
I'm going to use elimination.
y+x=98
y-x=22
-----------
2y+0x=120 SIMPLIFY 2y=120 SIMPLIFY y=60.
Substitute that into either equation and you get y=60 and x=38
Have a nice day! :)
Answer:
11, 14, 17, 20
Step-by-step explanation:
An arithmetic sequence has a common difference d between consecutive terms.
Consider 2, 6, 18, 54
6 - 2 = 4, 18 - 6 = 12, 54 - 18 = 36 ← no common difference, not arithmetic
Consider 3, 6, 12, 24
6 - 3 = 3, 12 - 6 = 6, 24 - 12 = 12 ← no common difference, not arithmetic
Consider 11, 14, 17, 20
14 - 11 = 3, 17 - 14 = 3, 20 - 17 = 3 ← common difference of 3, so arithmetic
Consider 7, 11, 13, 18
11 - 7 = 4, 13 - 11 = 2, 18 - 13 = 5 ← no common difference, not arithmetic
The arithmetic sequence is 11, 14, 17, 20
