we know that
the area of the complete square is equal to
where
b is the length side of the square
so
m²
the area of one corner is equal to the area of a triangle
so
the area of corners is equal to
the area A of the resulting figure as a function of x is equal to
area of the square minus the area of corners
m²
the answer is
m²
After trial and error, you discover that - 2 works.
-2 || 3 16 18 -4
-6 -20 4
====================================
3 10 - 2 0
What you have left is a quadratic
3x^2 + 10x - 2 You can just use the quadratic formula to solve for the other 2 roots.
x1 = [ - 10 +/- sqrt(10^2 - 4*3*(-2) ) ] / 6
x1 = [ -10 +/- sqrt (100 + 24) ) /6
x1 = [ - 10 +/- sqrt(124) ) / 6
x1 = [ - 10 +/- 11.14 ] / 6 = 0.1893
x2 = [ - 21.14 ] / 6 = - 3.522
Answer
x1 = - 2
x2 = 0.1893
x3 = - 3.522
