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skelet666 [1.2K]
3 years ago
11

Solve for F: C=5/9(F-32) please explain process thanks

Mathematics
2 answers:
DerKrebs [107]3 years ago
7 0
<u>C = 5/9 (F - 32)</u>

Multiply each side by 9/5 :

9/5 C = F - 32

Add 32 to each side:

<u>F = 9/5C + 32</u>
timama [110]3 years ago
4 0
C=\frac{5}{9}(F-32)\ \ \ \ /\cdot\frac{9}{5}\\\\F-32=\frac{9}{5}C\ \  \ \ /+32\\\\F=\frac{9}{5}C+32\\\\F=\frac{9C}{5}+\frac{160}{5}\\\\F=\frac{9C+160}{5}
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PLZZZZ HLPPPPP MEEEEEEEE
kati45 [8]

Answer: y ≥ (3/5)*x - 3

Step-by-step explanation:

In the graph, we can see that we are above a bold line, that goes through the points (0, -3) and (5, 0)

First, let's find the equation for this line:

y = a*x + b

the value of a is the slope and is equal to:

a = (0 - (-3))/(5 -0) = 3/5

and the value of b is the point where the line intersects the y-axis, in this case, b = -3

then our line is

y = (3/5)*x - 3

As the shaded part is above the line, this equality represents the minimum value that y can take for a given x, and because the line is not a doted line, we know that the equality is valid, so we must use the ≥ symbol.

y ≥ (3/5)*x - 3

4 0
3 years ago
50 POINTS EACH HEEEEELP !!!!!
Phoenix [80]

Hello there,

The <em>answer is </em>A' (-3,2).

<h3>Step-by-step explanation:-</h3>

From the image shown on the xy-plane, the coordinate of point A is at (3,-2).

The rule for rotation by 180° about the origin is (x,y)→(-x, -y), where (x,y) is the coordinate of image and (-x, -y) is the coordinate of the resulting pre-image.

Given the coordinate point A(3,-2), if this coordinate is rotated 180°, the resulting point A' will be located at (-3,-(-2)) = (-3,2).

Therefore, the answer will be <u>A'(-3,2)</u>

✍️ <em>by </em><em>Benjemin</em> ☺️

8 0
2 years ago
Read 2 more answers
I need help asap pls
sp2606 [1]

9514 1404 393

Answer:

  a) ∠DAE = 33°; ∠ABD = 57°

  b) ∠CEB = 90°

  c) ∠ABE = 22°

  d) ∠ADE = 15°

Step-by-step explanation:

The diagonals of a rhombus meet at right angles. Each bisects the corner angles at its ends. Adjacent angles are supplementary, opposite angles are congruent, and each diagonal creates two isosceles triangles.

a) ∠DAE = 90° - ∠ADE = 90° -57°

  ∠DAE = 33°

  ∠ADE = ∠ABD = 57°

__

b) ∠CEB = 90° . . . . . the diagonals meet at right angles

__

c) ∠ABE = 44°/2

  ∠ABE = 22°

__

d) ∠ADE = 90° -(1/2)∠DAB = 90° -150°/2

  ∠ADE = 15°

8 0
3 years ago
If sin theta = sqrt(2/2), which could not be the value of theta?
Nataliya [291]

The solution would be like this for this specific problem:

sin(θ°) = √(2)/2 

θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° − sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ 

360°*0 + 45° = 45° 
360°*0 + 135° = 135° 
360°*1 + 45° = 405° 

<span>sin(225°) = -√(2)/2

</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta cannot be 225 degrees.

4 0
3 years ago
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Solve the following system of equations {-2x+y=2, 3x-2y=4
Morgarella [4.7K]
The solution is (-8,-14)
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3 years ago
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