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frosja888 [35]
3 years ago
8

The stem-and-leaf plot shows the distances, in miles, that a group of owners of new cars drove one weekend.

Mathematics
1 answer:
evablogger [386]3 years ago
3 0
Six people. because if you count theres 55, 56,58,58, 63,63  so thats six people.
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There is a set of 12 cards numbered 1 to 12. A card is chosen at random. Event A is choosing a number less
kaheart [24]

The number of permutations of picking 4 pens from the box is 30.

There are six different unique colored pens in a box.

We have to select four pens from the different unique colored pens.

We have to find in how many different orders the four pens can be selected.

<h3>What is a permutation?</h3>

A permutation is the number of different arrangements of a set of items in a particular definite order.

The formula used for permutation of n items for r selection is:

    ^nP_r = \frac{n!}{r!}

Where n! = n(n-1)(n-2)(n-3)..........1 and r! = r(r-1)(r-2)(r-3)........1

We have,

Number of colored pens = 6

n = 6.

Number of pens to be selected = 4

r = 4

Applying the permutation formula.

We get,

= ^6P_4

= 6! / 4!

=(6x5x4x3x2x1 ) / ( 4x3x2x1)

= 6x5

=30

Thus the number of permutations of picking  4 pens from a total of 6 unique colored pens in the box is 30.

Learn more about permutation here:

brainly.com/question/14767366

#SPJ1

6 0
1 year ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
The smaller triangle is the image of the larger triangle after a dilation. The center of the dilation is (4,2). What is the scal
zzz [600]
Small triangle: <span>The side // x axis has a length of 4
Large triangle: The side // x axis has a length of 12

So Small/Large = 4/12 = 1/3

Small triangle: <span>The side // y axis has a length of 3
Large triangle: The side // y axis has a length of 9


</span><span>So Small/Large = 3/9 = 1/3

So the scale factor to obtain this dilatation is 1/3</span>

</span>
7 0
3 years ago
Read 2 more answers
Find the HCF and LCM of: x^3+27,2x^3-6x^2+18x,x^2-3x+9​
r-ruslan [8.4K]

Answer:

hcf:3x^3-6x^2+y^2-3x+54

lcm:2(x+3)(x^2-3x+9)(x^3-3x^2+9)(y^2-3x+9)

7 0
2 years ago
The length of the hypotenuse is??
yawa3891 [41]

Answer:

x = 14.31

Step-by-step explanation:

According to PYTHAGORAS Theorem,

let the Hypotenuse be x

{6}^{2}  +  {13}^{2}  =  {x}^{2}  \\ 36 + 169 =  {x}^{2}  \\ 205 =   {x}^{2}   \\  \sqrt{205}  = x \\ x = 14.31

5 0
3 years ago
Read 2 more answers
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