Question

You play a game that involves spinning the money wheel shown. you spin the wheel twice find the probability that you get more than $500 on your first spin and then go bankrupt on your second spin. round your answer to the nearest tenth

Answer 1

Answer:

Probability that you get more than $500 on your first spin and then go bankrupt on your second spin is:

0.02

Step-by-step explanation:

There are 24 segments on the wheel in total.

6 segment are of more than $500 and 2 are the bankruptcy spaces.

P(more than $500 on first spin and bankrupt on second spin)

=P(more than $500 on first spin)×P(bankrupt on second)

=

$\dfrac{6}{24}\times \dfrac{2}{24}\\ \\=\dfrac{1}{4}\times \dfrac{1}{12}\\ \\=\dfrac{1}{48} \\\\=0.02$

Hence, probability that you get more than $500 on your first spin and then go bankrupt on your second spin is:

0.02

Answer 2

There are 24 segments on the wheel in total. 1 segment is the $500 and 2 are the bankruptcy spaces. You would then multiply the two fractions 1/24 and 2/24 (the chances of getting each result) to get the answer. 1•2=2 and 24•24=576 making the fraction 2/576. Then you would simplify by dividing both sides by 2 which equals the final answer 1/288.