Ask question

Ask question

All categories

Marta_Voda [28]

2 years ago

15

Picture above please solve

2 answers:

Y_Kistochka [10]2 years ago

6 0

Answer:

1) 3x(3x-1)

2)5(9x^2-3x+1)

Andrei [34K]2 years ago

6 0

Answer:

3x(3x - 1)
$5(9x^{2} - 3x + 1)$

I hope this helps!

You might be interested in

From home, Mary’s work is two thirds along the way to training. Training is 2.5km from work. Mary normally goes to work, then tr

polet [3.4K]

First thing to do is to illustrate the problem, Since it was mentioned that work was along the way to training, the order is shown in the picture. Mary's home and workplace are nearer compared to her training center. It is also mentioned that the distance between work and home, denoted as x, is 2/3 of the total distance from home to training. The total distance is (x + 2.5). Thus,

x = 2/3(x+2.5)
x = 2/3 x + 5/3
1/3 x = 5/3
x = 5 km

Thus, the distance from home to work is 5 km. This means that Mary has to walk this distance twice to return home to get her shoes. Then, she will travel again the total distance of 5+2.5 = 7.5 km to get to her training center. So,

Total distance = 2(5km) + 7.5 km
Total distance = 17.5 km

3 0

3 years ago

Based on a sample of 100 employees a 95% confidence interval is calculated for the mean age of all employees at a large firm. Th

babymother [125]

Answer:

a

$\= x = 40.85$

b

$E = 5.85$

Ca

$t_c = 2.08$

Cb

$t_c = 1.282$

Explanation:

From the question we are told that

The sample size is n = 100

The upper limit of the 95% confidence interval is b = 47.2 years

The lower limit of the 95% confidence interval is a = 34.5 years

Generally the sample mean is mathematically represented as

$\= x = \frac{a + b }{2}$

=> $\= x = \frac{47.2 + 34.5 }{2}$

=> $\= x = 40.85$

Generally the margin of error is mathematically represented as

$E = \frac{b- a }{ 2}$

=> $E = \frac{47.2- 34.5 }{ 2}$

=> $E = 5.85$

Considering question C a

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

The sample size is n = 22

Given that the sample size is not sufficient enough i.e $n < 30$ we will make use of the student t distribution table

Generally the degree of freedom is mathematically represented as

$df = n- 1$

=> $df = 22 - 1$

=> $df = 21$

Generally from the student t distribution table the critical value of $\frac{\alpha }{2}$ at a degree of freedom of 21 is

$t_c =t_{\frac{\alpha }{2} , 21 } = 2.08$

Considering question C b

From the question we are told the confidence level is 80% , hence the level of significance is

$\alpha = (100 - 80 ) \%$

=> $\alpha = 0.20$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$t_c =Z_{\frac{\alpha }{2} } = 1.282$

4 0

2 years ago

If candler and oteen are 3 1/2 inches apart on the map, what is the actual distance between Candler and oteen in miles

givi [52]

They would be 0.00005524 miles apart because 1 in equals 0.00001578 miles

6 0

3 years ago

Is the square root of 6 a solution to x squared equals 36

Simora [160]

6^2 = 36
thats what you meant?

7 0

3 years ago

Read 2 more answers

Find the area of each triangle. Round values to the nearest tenth. Show your math thinking.

NeTakaya

7 x 7 = 49. 49/2 = 24.5
The area is 24.5 units squared.

4 0

2 years ago