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3 years ago

Indicating whether the following statements are True (T) or False (F).

1 answer:

7 0

1. The difference of two rational numbers is always a natural number. TRUE
2. The ratio of two rational numbers is always positive .FALSE

3. The difference of two rational numbers is always a rational number. TRUE

4. The quotient of two rational numbers is always a real number (provided the denominator is non-zero). FALSE

5. The quotient of two rational numbers is always a rational number (provided the denominator is non-zero).TRUE

6. The sum of two rational numbers is always a rational number. FALSE

7. The product of two rational numbers is always a rational number. FALSE

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The Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are

almond37 [142]

Answer:

For x = 0, P(x = 0) = 0.35

For x = 1, P(x = 1) = 0.54

For x = 2, P(x = 2) = 0.11

For x = 3, P(x = 3) = 0

Step-by-step explanation:

We are given that the Sky Ranch is a supplier of aircraft parts. Included in stock are 6 altimeters that are correctly calibrated and two that are not. Three altimeters are randomly selected, one at a time, without replacement.

Let X = the number that are not correctly calibrated.

Number of altimeters that are correctly calibrated = 6

Number of altimeters that are not correctly calibrated = 2

Total number of altimeters = 6 + 2 = 8

(a) For x = 0: means there are 0 altimeters that are not correctly calibrated.

This means that all three selected altimeters are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 3 altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_3$

So, the required probability = $\frac{^{6}C_3}{^{8}C_3}$

= $\frac{20}{56}$ = 0.35

(b) For x = 1: means there is 1 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 1 is not correctly calibrated and 2 are correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 2 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_2$

The number of ways of selecting 1 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_1$

So, the required probability = $\frac{^{6}C_2 \times ^{2}C_1 }{^{8}C_3}$

= $\frac{30}{56}$ = 0.54

(c) For x = 2: means there is 2 altimeter that is not correctly calibrated.

This means that from three selected altimeters; 2 are not correctly calibrated and 1 is correctly calibrated.

Total number of ways of selecting 3 altimeters from a total of 8 = $^{8}C_3$

The number of ways of selecting 1 correctly calibrated altimeters from a total of 6 altimeters that are correctly calibrated = $^{6}C_1$

The number of ways of selecting 2 not correctly calibrated altimeters from a total of 2 altimeters that are not correctly calibrated = $^{2}C_2$

So, the required probability = $\frac{^{6}C_1 \times ^{2}C_2 }{^{8}C_3}$

= $\frac{6}{56}$ = 0.11

(d) For x = 3: means there is 3 altimeter that is not correctly calibrated.

This case is not possible, so this probability is 0.

6 0

3 years ago

Use the graph to find the slope and y-intercept to write the equation in slope-intercept form.

Anna71 [15]

The x is -2 and the Y is -2

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2 years ago

Read 2 more answers

10 Points if you answer this!!!!

Vera_Pavlovna [14]

Answer:

1 result(s) found

9⋅(r−25)

Step-by-step explanation:

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3 years ago

Is 0.2487 a interger

BabaBlast [244]

No. 0.2487 is not an interger.

There are two big reasons for this:

1). There is no such thing as an ' interger ',
   so no number could be one.
   You probably mean ' integer '.

2). An integer is a whole number ... a number
    with no fraction part and no decimal part.
    0.2847 is all decimal, and not even big enough
      to make the smallest whole number. (That's ' 1 '.)

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3 years ago

The sum of x and 3/5 is 5/7

lord [1]

x = 5/7 - 3/5 = 25/35 - 21/35 = 4/35

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3 years ago