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Nadya [2.5K]
3 years ago
11

A pot full of water weighs 2 kg (the total combined weight of the pot and the water). If we spill out 20% of the water, the weig

ht of the pot and water together is 88% of the original weight. What is the weight of the empty pot in kg. Express your answer as a common fraction in lowest terms.
Mathematics
1 answer:
Katarina [22]3 years ago
4 0

the empty pot is 0.8 kg or 4/5 kg. just do the weight lost times five and you get the answer. (times five because 1/5th of the water was lost. so to get the original weight of the water you multiply by the divisor (5)). Then you subtracts 1.2 from 2 and your and is 0.8 or 4/5ths

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An irregular parallelogram rotates 360° about the midpoint of its diagonal. How many times does the image of the parallelogram c
tatuchka [14]

Answer:

2

Step-by-step explanation:

The question, is basically asking for the order of rotational symmetry for the parallelogram. This is 2, which means while spinning the parallelogram around its centre point 360 degrees, it looks exactly the same, or matches with its original at 2 points

4 0
3 years ago
“Below are in standard form and explain why.” Who’s correct?
horrorfan [7]

Answer:

From my knowledge and my research the answer is B! Thank you

Step-by-step explanation:


3 0
2 years ago
Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75.percent f
irinina [24]

Answer:

33%

Step-by-step explanation:

Assuming the weight of the mixture to be 100g**, then the weight of ryegrass in the mixture would be 30g.

Also, assume the weight mixture X used in the mixture is Xg, then the weight of mixture Y used in the mixture would be (100-X)g.

So we can now equate the parts of the ryegrass in the mixture as:

0.4X + 0.25(100-X) = 30

<=> 0.4X + 25 - 0.25X = 30

<=> 0.15X = 5

<=> X = 5/0.15 = 500/15 = 100/3

So the weight of mixture X as a percentage of the weight of the mixture

= (weight of X/weight of mixture) * 100%

= (100/3)/100 * 100%

= 33%

3 0
3 years ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
A bag of apples weighs 7 7/8 pounds. By weight, 1/15 of the apples are rotten. What is the weight of the good apples?
siniylev [52]
The good apples are 14/15 of the total apples. So multiply the total apples by the weight of good ones to find the solution. \frac{63}{8}*\frac{14}{15} = \frac{294}{40} = 7\frac{7}{20}lbs
4 0
3 years ago
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