30 pencils multiplied by 1/6 is equal to 30/6. Reduce 30/6 to lowest term by dividing 30 by 6. The quotient of 30 and 6 is 5. Therefore, Jake used 1/6 or 5 pencils of the 30 pencils in a pack.
Answer:
16 ways
Step-by-step explanation:
Number of available options other than the base model = 4
Hence ;
Jacobsen can choose :
Base model OR (base model + one option) OR (base model + 2 options) OR (Base model + 3 options) OR (Base model + 4 options)
4C0 + 4C1 + 4C2 + 4C3 + 4C4
Recall:
nCr = n! / (n-r)!r!
Using calculator :
4C0 + 4C1 + 4C2 + 4C3 + 4C4
1 + 4 + 6 + 4 + 1
= 16 ways
W + 54 = s
w + 54 = 72
Answer: C
Hope this helps!! :)