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Musya8 [376]
4 years ago
12

Consider the sequence given by the formula a(n + 1) = 5a(n) and a(1) = 2 for n ≥ 1.

Mathematics
1 answer:
lisov135 [29]4 years ago
7 0

Answer:

See explanation below

Step-by-step explanation:

As the problem states, a(1) = 2. This is the first term

To get the other 4 terms, we just need to replace in the given formula, the values of n from 1 to 5:

If the formula is a(n+1) = 5a(n), then to get a(2) it would be, a(1+1) = 5a(1), and the other terms would be the same procedure

a(2) = 5a(1) = 5 * 2 = 10

a(3) = 5a(2) = 5 * 10 = 50

a(4) = 5a(3) = 5 * 50 = 250

a(5) = 5a(4) = 5 * 250 = 1250

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Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))
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By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ \sqrt[n]{z} =  \sqrt[n]{a} \ (cos \  \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )
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For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
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∴ The modulus of the fourth root = \sqrt[4]{z} =  \sqrt[4]{81} = 3

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The angle of the given complex number = \frac{3 \pi}{8}
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Part (C): find all of the fourth roots of this

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The third root = z_{3} = 3 ( cos \  \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})
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