What is the base area of Box 3?
2 answers:
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Answer:
Given:-
The length of copper wire (L) = 270 cm
Area of cross-sectional (A) = 0.030
and specific resistance (ρ) = ohm-cm.
Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)
then, ohm
Simplify:
R = 0.0162 ohm = ohm
Therefore, the resistance of copper wire is, Ω
Answer:
The equation of the straight line is 4x +y = 1
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given points are (-1,5) and ( 2,-7)
Slope of the line
slope of the line m = -4
<u><em>Step(ii):-</em></u>
The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4
y - 5 = -4 ( x-(-1))
y -5 = -4 x -4
4 x + y -5 +4=0
4x +y -1 =0
<u><em>Final answer:-</em></u>
The equation of the straight line is 4x +y = 1
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