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levacccp [35]
3 years ago
10

This brain plus is BS u cant do anything all the stuff i need is blocked

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0
If you need help with anything you can post it. 
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where are the statements so i can help

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Four polynomials are shown below:
nikklg [1K]
Both B and D are 3rd degree, but only D is a 3rd degree binomial because it has only 2 terms. The answer is D.
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Is the point (4,2) the solution to the system? Why or why not? Explain your reasoning.
VMariaS [17]
Solve the top equation to get on variable on one side
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4 0
2 years ago
Henry buys a large boat for the summer, however he cannot pay the full amount of $32,000 at
Anna007 [38]

Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

Step-by-step explanation:

Loan payment per month=Amount to pay÷discount factor

Mathematically  P=A÷D

where D is the discount factor calculated using the formula;

\frac{(1+i)^n-1}{i(1+i)^n}

where i=periodic interest rate=annual rate divided by number of payment periods

A is the amount to pay after downpayment

P is the loan monthly payment amount

n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

Periodic payments, n=4×12=48

Finding the discount factor D;

D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05

To get the amount to pay monthly divide the loan to pay with the discount factor

=\frac{18000}{43.05} =418.14

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

8 0
2 years ago
What’s 20 over 14 as a percentage
sergey [27]

Answer: 14 / 20 = 70%

Step-by-step explanation:

8 0
3 years ago
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