Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Answer:
Option E, Floppy ears are dominant over straight ears; coat color is determined by incomplete dominance
Explanation:
Let the allele for floppy ears be "F" and the allele for straight ears be "f"
And Let the allele for black coat color be "B" and the color for white coat color be "b"
Now, the cross is carried out between the first group having floppy ears and white coat color (FFbb) and the second group having straight ears and black coat color (ff BB)
The 16 offspring have genotype FfBb
Phenotype of 16 offspring is Floppy ears and grey coat
Ff represents the floppy ear , thus "F" is dominant over "f"
Bb represents the grey color which is a case of incomplete dominance in which none of the real trait i.e black or white is expressed.
Hence, option E is correct
DNA can be transferred naturally between species by breeding.
Answer: Repolarization occurs Potassium ions continue to diffuse out of the cell after the inactivation gates of the voltage-gated sodium ion channels begin to close.
