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3 years ago

15

Sebastian has 10 apps on his ipad. He discovers 3/4 of the apps are learning games.How many learning games are on sebatians ipad

?

1 answer:

mars1129 [50]3 years ago

7 0

Answer:

Three fourth's of 10 is 7.5 if you round that up there are 8 learning games are on Sebastian's ipad

Step-by-step explanation:

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Select all the values that cannot be probabilities a. 3/5b. 1c. -0.45d. 0.06e. 1.16f. 0g. 5/3h. √2

nikitadnepr [17]

Answer:

c,-0.45 ,

e. 1.16

g. 5/3

h. √2

Cannot be probability.

Step-by-step explanation:

Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.

0≤P(A)≤1

Any value outside this boundaries cannot be probability.

Therefore, -0.45,1.16,5/3 and √2 cannot be probability.

4 0

3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

It takes Dariya 35 seconds to download 5 songs from the Internet. How can the number of seconds it would take Dariya to download

netineya [11]

Answer:

49

Step-by-step explanation:

35/5=7

7x7=49 seconds

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3 years ago

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What is the coefficient of the x6y3 term in the expansion of (x + 2y)9?

kodGreya [7K]

Please look to the attachment

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3 years ago

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SOMEONE PLZ HELP IM SO LOST ILL GIVE U BRAINLIEST

hammer [34]

Answer:

What is a Proof?

A series of steps, with justifications, that verifies a theorem or relationship exists

Types of Proofs

Two-column Proofs a table with two columns; the first column is the mathematical statement, and the second column is the justification

Paragraph Proofs a type of proof that explains the rationale for each step using complete sentences in paragraph form

Flow Chart Proofs a diagram that contains the steps of the proof and the justification for each one

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