Answer:
Step-by-step explanation:
A right angle triangle is formed.
The length of the guy wire represents the hypotenuse of the right angle triangle.
The height of the antenna represents the opposite side of the right angle triangle.
The distance, h from base of the antenna to the point on the ground to which the antenna is attached represents the adjacent side of the triangle.
To determine h, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Therefore,
41² = 32.8² + h²
1681 = 1075.84 + h²
h² = 1681 - 1075.84 = 605.16
h = √605.16
h = 24.6 m
To determine the angle θ that the wire makes with the ground, we would apply the the cosine trigonometric ratio.
Cos θ = adjacent side/hypotenuse. Therefore,
Cos θ = 24.6/41 = 0.6
θ = Cos^-1(0.6)
θ = 53.1°
If a field is 900 meters squared and one side is twice as big as the other how big is each side
Remark
I would have had the answer a whole lot sooner if I would have read the question properly. The figure in the circle is called a cyclic quadrilateral. It has the odd property that the angles that are opposite each other add up to 180o.
So DEB + DCB = 180o
DEB = 180 - 87
DEB = 93o
Note: The arcs marked 60 and 76 have nothing whatever to do with this problem.
<span> 3(x+2y)+5x−y+1
Use distributive property
3x+6y+5x-y+1
Add 5x to 3x
8x+6y-y+1
Subtract y from 6y
Final Answer: 8x+5y+1</span>
