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lord [1]
3 years ago
6

(8-9)-(9+3)*5 5+(5+5+6)+9 (5/3-3) 2*3+(4*2)/2

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0

Answer:

Step-by-step explanation:

Next time, please include the instructions.  I am assuming that the instructions state, "evaluate the following."

a) (8-9)-(9+3)*5  According to order of operations rules, we must do any work inside parentheses first, followed by any multiplication or division.  Here we calculate 8-9, obtaining -1, and 9+3, obtaining 12.  Then we have:

(-1) - (12)*5.  We must multiply here before subtracting:  -60 - 1 = -61.

b)  5+(5+5+6)+9    Do the addition inside parentheses first, obtaining:

5+(16)+9.  Now add up 5, 16 and 9:    30.

c) (5/3-3)    Do the division first, obtaining 5/3, and then subtract 3 (or, using the LCD, subtract 9/3):  5/3 - 9/3 = -4/3

d) 2*3+(4*2)/2  Do the multiplication first:  6 + (8)/2

Next, do the division:  6 + (4) = 10

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Step-by-step explanation:

The question is a 2-two-step Pythagoras theorem. (c^2 = a^2 + b^2)

Consider as such, If I were to draw a diagonal line along the base of the cube what is the length of the diagonal line. To find out that we use the theorem. We can substitute a for 5 and b for 5 as well. So

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Then since the line side of the cube is on a 3d angle we need to do the same process again but now using the imaginary diagonal line that we just calculated and the height (5).

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