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NeX [460]
3 years ago
6

12.1.33 Question Help Suppose that 62​% of families living in a certain country own an HDTV and 16​% own a computer. The Additio

n Rule might​ suggest, then, that 78​% of families own either an HDTV or a computer. ​What's wrong with that​ reasoning?
Mathematics
1 answer:
poizon [28]3 years ago
6 0

Answer:

Step-by-step explanation:

Suppose :

62% own an HDTV

16% own a computer

Using the addition rule : suggests that (62% + 16%) = 78% either own an HDTV or a computer.

The reasoning is wrong because ; since it is possible to own both an HDTV and also own a computer at the same time, the outcome of the addition rule is wrong as both events are independent. If both event cannot occur at the same time (mutually exclusive event) , then, the addition rule may be applied,. But since both can occur independently and each family can own an HDTV while also owning a computer, then the addition rule is wrong for the scenario described.

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2² - y - 5 = 0 

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4 years ago
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Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

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