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Oliga [24]
3 years ago
10

A 70-year-old male presents with back pain, fever, and weight loss. He reports that he had a recent respiratory infection from w

hich he thought he recovered. Tests revealed increased white blood cell count, and a diagnosis of endogenous osteomyelitis was made. The primary organism causing this condition is: a. Staphylococcus aureusb. Salmonella
c. Mycobacterium
d. Haemophilus influenza
Biology
1 answer:
Arlecino [84]3 years ago
5 0

Answer:

The answer is C. Mycobacterium.

Explanation:

According to the symptoms the male demonstrates in the question, the primary organism causing these should be Mycobacterium because it is a bacteria that is associated with causing diseases such as Tuberculosis and Leprosy.

The symptoms of Tuberculosis include most of the listed ones which are fever, weakness and weight loss.

The diagnosis of endogenous osteomyelitis also indicates that the back pain is caused by the tuberculosis as well, Tuberculous Osteomyelitis to be exact which is also defined as Skeletal Tuberculosis.

I hope this answer helps.

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Hypothesis: If the type of the food available changes, then the frequency of beak types will change, because birds with beaks mo
dangina [55]

The correct answer is: If generation 3 had flock distributions similar to those shown in the graph below.

After the change in food, the beak phenotype changes in order to adapt. So, if fruit is removed, the phenotype of birds’ beaks should change according to the change in environment. The graph below shows that there is no change, so it wouldn’t support the hypothesis that food changes beak types.

5 0
4 years ago
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F the diploid number of chromosomes in a dog's skin cell is 48, what is the number of chromosomes in a dog's sperm cell?
IceJOKER [234]
Is 24 because 48 divided by 2 is equal to 24
3 0
3 years ago
Use the key to identify each species. Write the letter of each species (A to G) in the correct
sveticcg [70]

Dichotomous keys are useful to identify organisms according to their morphological traits. The given key provides enough macroscopic morphological traits to identify these Arachnida species.

-----------------------------------------------

A dichotomous key is a significantly useful tool to classify organisms. The key provides an easy and fast way for identification by describing different morphological traits, leading you to the correct taxonomic classification.

The key provides morphological descriptions about different taxonomic groups in an easy way to identify these traits in your individual.

The term <em>dichotomous</em> refers to how information is provided. You will always have two options (a and b, or 1 and 2), and you will have to choose one of them according to the characteristics of your organism.  

In the exposed example, as the key provides morphological traits, we will separate the organisms<u><em> into two groups</em></u>:

  • the group that has the trait
  • the group that does not have it.

By recognizing each trait in each of the individuals, we will get to identify the species.

1

(a)  Abdomen <u>with a </u><u>tail</u> --------------------------- The only option is E

(b)  Abdomen <u>without a </u><u>tail</u><u> </u>----------------------  All the others A, B, C, D, F, G

2  ---<em>Only for  group A, B, C, D, F, G---</em>

(a) <u>Legs</u><u> much longer </u>than abdomen and  cephalothorax ----------A and G

(b)<u> </u><u>Legs</u><u> not much longer</u> than abdomen and  cephalothorax----- B, C, D, F

3  ---<em>Only for  group A, G---</em>

(a) <u>Hairs</u> on the legs -----------------------------------The only option is A

(b) <u>No hairs</u> on the legs ------------------------------ G

4  ---<em>Only for  group B, C, D, F---</em>

(a) Cephalothorax or <u>abdomen</u><u> segmented</u> ----------------The only option is D

(b) Cephalothorax or a<u>bdomen not segmented</u> ----------- B, C, F

5  ---<em>Only for  group  B, C, F---</em>

(a) Abdomen and cephalothorax <u>of the same size</u> --------The only option is F

(b) Abdomen and cephalothorax <u>of different size</u> -------B, C

6  ---<em>Only for  group B, C---</em>

(a) Body <u>covered with long</u><u> hair</u><u> </u>----------------------------------The only option is C

(b) Body<u> </u><u>not covered with</u><u> hair</u> ------------------------------------B

A  →  <em>Tegenaria domestica</em>

B  →  <em>Ixodes hexagonus</em>

C  →  <em>Tyroglyphus longior</em>

D  →  <em>Chelifer tuberculatus</em>

E  →  <em>Abaliella dicranotarsalis</em>

F  →   <em>Poecilotheria regalis</em>

G  →  <em>Odielus spinosus</em>

---------------------------------------------------

Related link: brainly.com/question/2235448?referrer=searchResults  

                    brainly.com/question/17365165?referrer=searchResults  

4 0
3 years ago
You find a beaker filled with an unknown clear liquid on your lab bench. what should you do?
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Treat the liquid as if it is hazardous. Inform your teacher/instructor so you will be notified of the proper disposal technique.
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Which regions of the nephron function independently of hormonal control for the most part?
alexgriva [62]

Answer:

Renal corpuscle, proximal tubule, and loop of henle.

Explanation:

Renal corpuscle is blood filtering part of the nephron which consist of Bowman's capsule and glomerulus. It works independently of hormonal control and filter the blood circulate through this glomerulus.

Proximal tubule is the component of nephron which starts from the renal pole of Bowman's capsule to the loop of henle and it involves in the selective reabsorption of glucose, peptides, water and other nutrients from tubule to the blood. It works independently of hormonal control.

Loop of henle is the U shaped part of nephron which is responsible for absorption of water and sodium chloride from urine to back into blood circulation. It is also work independently of hormonal control.

3 0
4 years ago
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