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3 years ago

The regular price of a shirt is $24. The sale price is $18. The sale price is what percent of the regular price?

Mathematics

1 answer:

Brrunno [24]3 years ago

4 0

$18=24x$

$\frac{18}{24}=\frac{24x}{24}$

$0.75=x$

The discount price is 75% of the original price :)

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Factor completely:<br> 21) x2 – 2x - 8

mojhsa [17]

Answer: x = -2 and 4

Step-by-step explanation:

x^2 - 2x - 8 = 0

(x - 4)(x + 2) = 0

4 0

3 years ago

The length of the sides of four triangles are given. Determine which triangle is not a right triangle.a.5 mm, 12 mm, 13 mmb.20 m

gizmo_the_mogwai [7]

For a right triangle, the sum of the squares of two shorter side should be equal to the square of the third side. The calculations for each choices are shown below.

a. (5 mm)² + (12 mm)² = 169 mm² ; (13 mm)² = 169 mm² ; EQUAL
b. (20 mm)² + (48 mm)² = 2704 mm² ; (52 mm)² = 2704 mm² ; EQUAL
c. (6 mm)² + (8 mm)² = 100 mm² ; (10 mm)² = 100 mm² ; EQUAL
d. (11 mm)² + (24 mm)² = 697 mm² ; (26 mm)² = 676 mm² ; NOT EQUAL

Therefore, the answer is letter D.

7 0

3 years ago

What is the domain of the graph?

maksim [4K]

Domain:
-4 ≤ x ≤ 3
or in different form:
x ∈ [-4; 3]

4 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

PLS HELP

Andrews [41]

Answer:Evaluate the following exponential function when x = 1.

f (x) = 9 (12)Squared X + 12

F(1) =

Evaluate the following exponential function when x = 1.

f (x) = 9 (12)Squared X + 12

F(1) =Evaluate the following exponential function when x = 1.

f (x) = 9 (12)Squared X + 12

F(1) =

Step-by-step explanation:Evaluate the following exponential function when x = 1.

f (x) = 9 (12)Squared X + 12

F(1) =

3 0

2 years ago