<h3>
Answer:</h3>
f(x) = -(x -2)² +3
<h3>
Step-by-step explanation:</h3>
We can fill in the vertex (h, k) values immediately in the vertex form ...
... f(x) = a(x -h)² +k
To find the value of a, we solve the equation for a at some point other than the vertex. The given point is (0, -1), so we can use that:
... -1 = a(0 -2)² +3
... -4 = 4a . . . . . . . . . subtract 3, simplify
... -1 = a . . . . . . . . . . . divide by 4
Now, we know the function is ...
... f(x) = -(x -2)² +3
X, x+1, x+2, x+3 are 4 consecutive integers
2(x + x+2) = 5(x+3) - 26
2(2x+2) = 5(x+3) - 26
4x + 4 = 5x + 15 - 26
4x + 4 = 5x - 11
15 = x
15, 16, 17, 18
x, x+2, x+4 consecutive even integers
2(x+4)+11 = x + 9
2x + 8 + 11 = x + 9
2x + 19 = x + 9
x = -10
-10, -8, -6
is the disk of radius 1 parallel to the 
-plane and lying in the plane 
. Parameterize this surface by
with 
and 
. Take the normal vector to to be
(the orientation doesn't matter because this is a scalar surface integral)
Then
Step-by-step explanation:
y = 4x-1
2x+y = 5
2x+(4x-1) = 5
6x - 1 = 5
6x = 6
x = 1
Answer:
Step-by-step explanation:
the last coordinate would be8,0 because i did it on graph paper and checked it a bunch of time even with my math teacher
