State the domain and range of the following relation x^2+y^2=16

Mathematics

1 answer:

Vlada [557]2 years ago

8 0

The domain and range is [-4, 4] and [0, 4]

<h3 /><h3>What is Domain and range?</h3>

The domain of a function is the set of values that we are allowed to plug into our function.

The range of a function is the set of values that the function assumes.

x² + y² = 16

y = √16 - x²

For domain under root should not be negative quantity,

16 - x²≥0

16≥x²

So, x≤4 or x≥4

Thus, the domain is [-4, 4]

Range:

y is maximum at x=0, y=4

y is minimum at x=4, y=0

Thus, range = [0, 4]

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$1.3\cdot 10^3\text{ J}$

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

$W=Fd$ , where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by $F_g=mg$ , where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, $F_g=75\cdot 9.8=735\text{ N}$ . Since she raises her body 4.0 meters, the work done must be $W=Fd=735\cdot 4=2940\text{ J}$ .