Question

Ajoba and Prav drive to work. Ajoba drives 45 miles in 2.5 hours. Prav drives 74 km in 1 hour 15 minutes. Work out the difference between their average speed in km/h. 1 mile = 1.6 km

Answer 1

Answer:

Ajoba: 28.8km/h

Prav: 59.2km/h

The difference in speed is: 59.2-28.8=30.4km/h

Step-by-step explanation:

Ajoba:

d=45mi Convert to km // $45mi(\frac{1.6km}{1mi} )=72km$

t=2.5h

v=? 28.8km/h

Prav:

d=74km

t=1h15m or 1.25h

v=? 59.2km/h

$Formula: d=v*t$

Solve for v;

$v=\frac{d}{t}$

$v=\frac{72km}{2.5h} \\v=28.8km/h$

--------------------------------------------

$v=\frac{d}{t}$

$v=\frac{74km}{1.25h} \\v=59.2km/h$