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olya-2409 [2.1K]
3 years ago
6

SOMEONE PLEASE HELP ME

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
<h2>The power of 5 is 9, which is an odd number. Therefore, it is not a square number or a perfect square.</h2>

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-4x+6y=-7<br> -13x-2y=-4 <br> Elimination or substitution
12345 [234]

Answer:

substitution

Step-by-step explanation:

7 0
3 years ago
10. Mrs. Simon is trying to find the amount of floor
luda_lava [24]
:

The area.


She is trying to find how to cover it, which would be the area of the floor.
5 0
3 years ago
Find the difference of(ab+8a+1)-(-6ab+4)
vagabundo [1.1K]
Hey there!

When finding the difference of expressions like these, there's a few things you should keep in mind. 

1. When finding the difference of two polynomials, multiply the polynomial that implied to be "negative" by –1 to expand the problem and make it easier to solve. 

2. You combine terms based on their unknown terms, like x, y, x², ab, etc. You cannot combine the terms x and x², but you can combine the terms 6b and 8b by adding them. 

3. You can rearrange your terms however you see fit. If a polynomial is implied as "positive", you can multiply that entire polynomial by +1 to get rid of the parentheses. 

With all that in mind, you can go ahead and solve for your difference, like so:

(ab+8a+1)-(-6ab+4)

(ab+8a+1) (-1(-6ab+4))

(ab+8a+1) + (6ab-4)

ab+6ab+8a+1-4

7ab+8a-3

7ab+8a-3 will be your difference. 

Hope this helped you out! :-)
8 0
3 years ago
Solve for x. <br><br> 12x/5 = 18
jarptica [38.1K]
For this problem you have to isolate the variable. To do this you must inverse the operations. Multiply 18 by 5, then divide by 12 to get your answer of 7.5
3 0
3 years ago
The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is . The probabi
Tems11 [23]

Answer:

1/15

Step-by-step explanation:

When we form such three-digit numbers with distinct digits using the digits  1 , 2 , 3 , 5 , 8  and  9  (in all six digits all different), observe that the order of digits does matter. For example, if we make a number using digits  1 , 2 ,  and  3 , we can have  123 , 132 , 231 , 213 , 312  or  321 .

Hence we have to find number of  3  digit numbers that can be made from these six digits using permutation and answer is ⁶ P ₃ =  6  ×  5  ×  4  =  120 .

.How haw many of them will have first digit as even, we have two choices  2  and  8 . Once we have chosen  2

for hundreds place, we can have only  8  in units place and any one of remaining  4  can be used in tens place. Hence four choices, with  2  in hundreds place and another four choices when we have  8  in hundreds place (and  2  in units place) i.e. total 8  possibilities.

Hence, the probability, that both the first digit and the last digit of the three digit number are even numbers, is  8  /120  =  1 /15

.

4 0
3 years ago
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