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mr_godi [17]
3 years ago
8

What is the common ratio between successive terms in the sequence?

Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer:

- 2

Step-by-step explanation:

common ratio is - 2

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What is the most precise
Maru [420]
It is d i would include a visual picture but i’m lazy lol
7 0
3 years ago
A car company is going to issue new ID codes to its employees. Each code will have one digit followed by four letters. The lette
scoray [572]

2734375 employee ID codes can be generated

<em><u>Solution:</u></em>

Given that Each code will have one digit followed by four letters

The letter V and the digits 3, 4, and 5 will not be used

So, there are 25 letters and 7 digits that will be used

Assume that the letters can be repeated

Each code = 1 digit + four letters

digits 3 , 4 , 5 cannot be used

Therefore, the remaining digits are 1, 2, 6, 7, 8 , 9, 0

7 digits that will be used

One digit can be chosen from 7 digits in 7 ways

The first letter can be chosen from 25 letters in 25 ways

Since given that letters can be repeated

The second letter can be chosen from 25 letters in 25 ways

Similarly, the third letter can be chosen from 25 letters in 25 ways

Similarly, the fourth letter can be chosen from 25 letters in 25 ways

<u><em>Therefore, the total number of ways are:</em></u>

\rightarrow 7 \times 25 \times 25 \times 25 \times 25 = 7 \times 25^4\\\\ \rightarrow 2734375

Thus 2734375 employee ID codes can be generated

3 0
3 years ago
Frank has devised a formula for his catering business that calculates the number of meatballs he needs to prepare. The formula i
Aleonysh [2.5K]
<span>m = 4a + 2c

a = 25; c = 5

Replace a with 25. Replace c with 5.
Then evaluate the expression.

m = 4 * 25 + 2 * 5

m = 100 + 10

m = 110

Answer: 110 meatballs are needed.</span>
4 0
3 years ago
The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation
Olegator [25]
You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or       4k - 1 = 13.  Then 4k = 14, and k = 14/4, or (after reduction)  k = 7/2   

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.
3 0
3 years ago
12×5 is egual to what
Ira Lisetskai [31]

Step-by-step explanation:

12×5 =60

Ik it helps you so no problem

7 0
2 years ago
Read 2 more answers
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