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melamori03 [73]
3 years ago
13

Factorise the following by taking out a common binomial factor. 7(x - 3) - (x + 3)(x - 3)

Mathematics
2 answers:
g100num [7]3 years ago
7 0

Step-by-step explanation:

7(x - 3) - (x + 3)(x - 3)

(x - 3)(7 - (x + 3))

(x - 3)(7 - x - 3)

(x - 3)(4 - x)

zvonat [6]3 years ago
7 0

Answer:

(x - 3)(4 - x).

Step-by-step explanation:

The common binomial factor is (x - 3) so we have:

7(x - 3) - (x + 3)(x - 3)

= (x - 3)( 7 - (x + 3))

= (x - 3)(4 - x)

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Solve the following equations.<br> 3 ⋅ 62^x = 648
gayaneshka [121]

Answer:

x=1.56861

Step-by-step explanation:

62^x=648

By using logarithms it becomes easier to solve this question because of the properties they have

From the property of logarithms

loga^x=xloga

Take logarithms on both sides

log62^x=log648

\Rightarrow xlog62=log648

\Rightarrow x=\frac{log648}{log62}

\Rightarrow x=1.56861

x=1.56861

7 0
4 years ago
Please help me I would really appreciate it.
Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

5 0
3 years ago
Options 1,2,3 or4?<br><br> Help!<br> Last one I swear!
lapo4ka [179]

Answer:

option 3 = 3.75

Step-by-step explanation:

x is 3.75

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8 0
3 years ago
Read 2 more answers
Least to greatest -45/10,3/1000,-0.005,0.34
aleksklad [387]
-0.005,-45,0.34,3,10,1000
8 0
3 years ago
What are the sine and cosine ratios for a 30°–60°–90° triangle with a hypotenuse of 6, when θ = 60°?
Margaret [11]

Answer:

There are two ways to do this problem algebraically or trigonometrically.

Algebraically/geometrically

The ratios of the sides of a 30/60/90 tri. are x, x√3, 2x (short leg, long leg, hyp). Therefore, if the long leg is 6 'units'. then 6 = x√3. x = 6√3.

The hyp is 2x then the hypotenuse is 2(6√3) = 12√3, rationalizing is 12√3/3 = 4√3

Using Trig.

We can use sinx = y/r = opp/hyp. The long leg of 6 is opposite 60 degrees (pi/3).

Therefore, sin(pi/3) = 6/r =

r = 6/sin(pi/3) = 6/(√3/2) = 12/√3, when you rationalize you get 12√3/3 = 4√3

4 0
2 years ago
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