The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.
Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.
So, if we sum the first N odd numbers, we have
The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have
The second sum is simply the sum of N ones:
So, the final result is
which ends the proof.
1x68
2x34
4x17
Hope that helps
The number line would go from (-10 to 10)
Answer:
x=3
Step-by-step explanation:
Because the shape is a rhombus that means that WZ and XY are parallel
This means we can use the co-interior angles rule to conclude that ∠WZY and ∠XYZ add up to 180°
This means that ∠WZY is 44°
Because the shape in a rhombus ZX and WY are perpendicular
This means that ∠ZRY is a right angle (90°)
Because ZX and WY are perpendicular that means that ∠ZYX is split in half which makes ∠ZYW 68°
Because the angles in a triangle add up to 180°
(10x-8)+68+90=180
(10x-8)+158-158=180-158
10x-8+=22+8
10x/10=30/10
x=3
Answer:
52
Step-by-step explanation:
A(2) + B(2) = C(2)
10(2) + 24(2)
676 = C(2)
square root of 676
AC=26 BD=26
AC + BD
26 + 26 =
52
Hope this helps
