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marusya05 [52]
3 years ago
15

How do I figure out -3√12-2√27-2√45

Mathematics
1 answer:
SashulF [63]3 years ago
8 0

Answer:

−12√3−6√5 or Decimal: -34.201018

Step-by-step explanation:

-3√12-2√27-2√45

3√12=6√3

2√27=6√3

2√45=6√5

=6√3-6√3-6√5

=−12√3−6√5

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Find the probability of each event.
jeka57 [31]

Using the binomial distribution, it is found that there is a 0.0108 = 1.08% probability of the coin landing tails up at least nine times.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • The coin is fair, hence p = 0.5.
  • The coin is tossed 10 times, hence n = 10.

The probability that is lands tails up at least nine times is given by:

P(X \geq 9) = P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.5)^{9}.(0.5)^{1} = 0.0098

P(X = 10) = C_{10,10}.(0.5)^{10}.(0.5)^{0} = 0.001

Hence:

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0098 + 0.001 = 0.0108

0.0108 = 1.08% probability of the coin landing tails up at least nine times.

More can be learned about the binomial distribution at brainly.com/question/24863377

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5 0
2 years ago
The number of girls in the Middle School Cyber Club was 6 more than double the number of boys, and in total there were 48 middle
Wittaler [7]

Answer:

g = number of girls;

b= number of boys

we know that: g= 6+2b

     and that: g+b= 156 kids in total

so we may write  g+b=(6+2b)+b=6+3b

                 but g+b= 156

so 6+3b = 156 => 3b= 156-6=150 =>   b=150/3=50 => b = 50 (number of boys)

g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)  

Step-by-step explanation:

5 0
3 years ago
Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.
alexdok [17]

Answer:

The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.

There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9

Therefore for each and every one of the nine first digits there are 5 digits that the second can be.

Therefore ANSWER = 9 * 5 = 45 possible permutations.

2. The largest two digit number = 99

Subtract 57 and you get 42

ANSWER = 42

The forty two numbers are 58 ,59, 60, 61......98, 99

7 0
3 years ago
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viktelen [127]
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67 books will fit on the shelf.
4 0
3 years ago
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timofeeve [1]

This is least to greatest

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2.45

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2 2/5 , 2.45 , 2 2/3

7 0
3 years ago
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