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kicyunya [14]
4 years ago
9

Round each decimal to the nearest whole number 4.5​

Mathematics
1 answer:
Vikentia [17]4 years ago
3 0

its is the closet one too the right one

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In triangle ABC , side AB is 6 and side AC is 4: Which statement is needed to prove that segment DE is parallel to segment BC an
Andreyy89

Answer:

Segment AD is 3, and segment AE is 2.

Step-by-step explanation:

In a triangle, the line joining the mid points of two sides is parallel and half of the third sides of the triangle.

Here, ABC is a triangle,

In which,

AB = 6,

AC = 4,

D∈ AB and E∈AC

Let DE ║BC,

And, DE=\frac{1}{2}BC

In triangles ADE and ABC,

\angle ADE\cong \angle ABC  ( Alternative interior angle theorem )

\angle AED\cong \angle ACB

By AA similarity postulate,

\triangle ADE\sim \triangle ABC

∵ Corresponding sides of similar triangle are in same proportion,

\implies \frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}

\frac{AD}{AB}=\frac{AE}{AC}=\frac{BC}{2BC}

\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{2}

\implies AD = \frac{AB}{2}\text{ and }AE =\frac{AC}{2}

\implies AD = \frac{6}{2}=3\text{ and }AE =\frac{4}{2}=2

Hence, the correct option would be,

Segment AD is 3, and segment AE is 2.

4 0
3 years ago
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