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3 years ago

What is the slope of the line represented by the equation 6y-14x=5

Mathematics

1 answer:

ioda3 years ago

7 0

Answer:

slope = $\frac{7}{3}$

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 6y - 14x = 5 into this form

add 14x to both sides

6y = 14x + 5 ( divide all terms by 6 )

y = $\frac{14}{6}$ x + $\frac{5}{6}$ ← in slope- intercept form

with slope m = $\frac{7}{3}$ ← in simplest form

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3 years ago

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3 years ago

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11Alexandr11 [23.1K]

Answer:

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y=-3x+14

Step-by-step explanation:

Given the points

(4, 2)

(3, 5)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(4,\:2\right),\:\left(x_2,\:y_2\right)=\left(3,\:5\right)$

$m=\frac{5-2}{3-4}$

$m=-3$

We know that the slope-intercept form of the line equation is

$y=mx+b$

where m is the slope and b is the y-intercept

substituting m=-3 and the point (4, 2) to get the y-intercept i.e. b

$y=mx+b$

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Now, substituting b=14 and m=-3 in the slope-intercept form to determine the equation of a line in the slope-intercept.

$y=mx+b$

y=(-3)x+(14)

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Thus, the equation of the line containing (4,2) and (3,5) in the slope-intercept form will be:

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3 years ago