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m_a_m_a [10]
3 years ago
10

A chemical equation is shown below. pls and ty

Chemistry
1 answer:
makkiz [27]3 years ago
8 0

Answer:

The given equation is not balanced.

Explanation:

Chemical equation:

3H₂ + 3Cl₂   →  HCl

The balanced equation always have equal number of atoms on both side of equation. In this equation on left side there are six atoms of chlorine and six atoms of hydrogen are present while on right side only one atom of hydrogen and one atom of chlorine are present.

The balanced equation always follow the law of conservation of mass.

According to the law of conservation of mass, mass can neither be created nor be destroyed in a chemical reaction.

It means reactant and product always have same mass.

The given equation can written as balanced equation as follows,

Balanced chemical equation:

3H₂ + 3Cl₂   →  6HCl

There are equal number of atoms of hydrogen and chlorine are present on both side of equation so it follow the law of conservation of mass.

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Answer:

139.5 mL.

Explanation:

To solve this question we will be making use of dilution law which is given by the equation below;

C1 × V1 = C2 × V2. Where C1 = the initial concentration, V1 = Initial volume, C2 = final concentration, V2 = Initial volume.

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1) What is the mass of 6.2 mol of K2CO3?
lorasvet [3.4K]

Answer:

\boxed {\boxed {\sf 856.8648 \ grams \ of \ K_2CO_3}}

Explanation:

To convert from moles to grams, we must find the molar mass.

1. Molar Mass

First, identify the elements in the compound. K₂CO₃ It has potassium, carbon, and oxygen. Find these elements and their masses on the Periodic Table.

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  • C: 12.011 g/mol
  • O: 15.999 g/mol

Note the subscript of 2 after K and 3 after O. We must multiply oxygen's molar mass by 2, then oxygen's by 3, and add carbon.

  • 2(39.098 g/mol) + 3(15.999 g/mol) + 12.011 g/mol= 138.204 g/mol

2. Convert Moles to Grams

Use the molar mass as a fraction.

\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}

Multiply by the given number of moles: 6.2

6.2 \ mol \ K_2CO_3 *\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}

6.2  *\frac {138.204 \ g \ K_2CO_3}{1 }

6.2  * {138.204 \ g \ K_2CO_3}

856.8648 \ g \ K_2CO_3

There are <u>856.8648 grams</u> of potassium carbonate in 6.2 moles.

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