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bonufazy [111]
3 years ago
11

Which of the following ions has a pseudo-noble-gas electron configuration?

Chemistry
2 answers:
Darya [45]3 years ago
3 0

Answer:A pseudo-noble gas configuration is: 1s2 2s2 2p6 3s2 3p6 3d10. Cu^+ has this electron configuration.  The answer is C)

Explanation:

9966 [12]3 years ago
3 0
<h2>Answer:</h2>

\bold{Cu^+} ions have a "pseudo-noble-gas" electron configuration.

<h2>Explanation:</h2>

The ion with the (n-1) d^{10} electron configuration is known as Nobel gas. The nature of noble gas is that the cations in this electron configuration are stable.

<u>The Pseudo-noble gas has the electron configuration as: </u>

1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10}

Since, Cu^+ ion has the same configuration. The example of Nobel gas is, both InCl and InCl_3 are stable compounds. To form In^+ only the 5p^1 electron is removed leaving the [Kr] 5s^2 4d^{10} electronic configuration.

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Write the cell notation for the voltaic cell that incorporates each of the following redox reactions:(a) Al(s) + Cr³⁺(aq) → Al³⁺
Sladkaya [172]

The cell notation for the given voltaic cell is as follows

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

<h3>What is a voltaic cell?</h3>

The device in which electrons are transferred through an external source is known as a voltaic cell.

The electron flow of a Voltaic cell allows redox reactions to produce energy in the form of electricity.

It converts the energy of spontaneous redox reaction into electrical energy

An anode, a cathode, and a salt bridge are all parts of a voltaic cell's setup. The salt bridge serves to neutralize the system.

To write the cell notation, identify the oxidation and reduction reactions.

At the anode, oxidation takes place

Al(s) \longrightarrow Al^{3+} (aq) + 3e^-

At the cathode, reduction takes place

Cr^{3+} (aq) + 3e^- \longrightarrow Cr(s)

While writing cell notation, the anode is written on the left, and the cathode is written on the right

A single vertical line differentiates between the phases and a double vertical line represents the salt bridge.

Now, write the cell notation of the given Voltaic cell

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

Learn more about Voltaic cells:

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7 0
2 years ago
Calcule la normalidad de una solución
tensa zangetsu [6.8K]

Answer:

si por favor

Explanation:

5 0
3 years ago
Which is warmer -30C or -30 F?​
Burka [1]

-30°C is more warmer than -30°F...!

<h2>How??</h2>
  • Always Celsius is warmer than farheniet and also in coldness Celsius is colder than farheneit.
8 0
2 years ago
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Explain why a total lunar eclipse appears red.<br> I
DochEvi [55]

Answer:

During a total lunar eclipse, the Earth lies directly between the sun and the moon, causing the Earth to cast its shadow on the moon.

Explanation:

4 0
3 years ago
What mass of lead (II) chloride is produced when 200.0 mL of a 0.250 M solution of sodium chloride is mixed with 200.0 mL of a 0
kow [346]

Answer:

Option d. 6.95 g

Explanation:

First of all, we state the reaction:

2NaCl + Pb(NO₃)₂ → PbCl₂ +  2NaNO₃

We determine the moles of each reactant, to state the limiting

Firstly we convert volume frm mL to L

0.200 L . 0.250M = 0.05 moles of NaCl

0.200L . 0.250M = 0.05 moles of Pb(NO₃)₂

Acording to stoichiometry we know that relation is 1:2, so the limiting reagent is the NaCl.

For 1 mol of Pb(NO₃)₂ I need 2 moles of NaCl

For 0.05 moles of Pb(NO₃)₂ I would need, the double → 0.1 moles

(We only have, 0.05 moles of NaCl)

Stoichiometry to the formed product is 2:1

From 2 moles of NaCl I produce 1 mol of PbCl₂

From 0.05 moles I would produce, the half → 0.025 moles

Let's convert the moles to mass → 0.025 mol . 278.1 g / 1mol = 6.95 g

8 0
3 years ago
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