For this case we have an equation of the form:
h (t) = - (1/2) * a * t ^ 2 + vo * t + h0
Where,
vo: initial speed
a: acceleration:
h0: initial height.
We have the following equation:
h (t) = - 16t2 + 19t + 110
Therefore, the initial velocity is:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown:
vo = 19 feet / s
We need the question to help
Answer:
G
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. 1 Simplify 2+6-4d to -4d+8.
7 ( -4d + 8)
therefor, the answer is, 7( -4d + 8)