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horrorfan [7]
2 years ago
7

Whats the answer plz

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
4 0

Answer:

The correct answer should be A not 100% sure

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Marjani's garden contains roses, daffodils, and tulips. About 3/5 of the flowers are tulips. What percent of the flowers in Marj
SVEN [57.7K]
Since 3/5 are tulips, that makes the remaining flowers not tulips. Therefore, 2/5 of the flowers in her garden are not tulips. Hope this helps!
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What is the next number in the sequence 3, 12, 24, 33, 66
ExtremeBDS [4]
75.
Explanation: from 3 to 12, you add 9, and then double the 12 to get to 24, and then add 9 again to get to 33, and double it to get 66, so the pattern is to add 9 and then double.
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3 years ago
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Luke plots his favorite places to go in his town on a coordinate plane. His 4 favorite places, the skateboard park, the ice crea
raketka [301]

We are given that:

The skateboard park is located at the point (-3,5),

the ice cream shop is located at the point (-3,6),

and the comic book store is located at (4,6).

We are also given that the four coordinates forms a rectangle.

Here we already have two matching x- coordinates as -3 and y coordinates as 6.

Now we must have two matching x and y coordinates too.

As shown in figure , if we have the last coordinate as (4,5), it will complete the rectangle.

So answer is option B) (4,5) is the last coordinate at which his best friend lives.


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3 years ago
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Find the slope of the tangent to the graph of the given function at the indicated point. HINT [Recall that the slope of the tang
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=  8{x}^{7}

slope

8 {( - 8)}^{7}  =  -  {8}^{8}

6 0
3 years ago
Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
guajiro [1.7K]

Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

5 0
3 years ago
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