a₅ = 10
a₁₀ = 20
a₁₅ = x
-------------------------------------------------------------------------------------------------------------------
Note that from a₅ to a₁₀, there is a addition of 10. This means that for every x(₅) jump, you add 10 to the whole number.
-------------------------------------------------------------------------------------------------------------------
So in this case:
a₁₀ = 20
a₁₅ = x
a₁₀ (+₅) = 20 (+10)
a₁₅ = 20 + 10
a₁₅ = 30
Note that: a₁₅ = x = 30
-------------------------------------------------------------------------------------------------------------------
x = 30, or (A) is your answer
-------------------------------------------------------------------------------------------------------------------
hope this helps
Answer:
<h2>231cm²</h2>
Step-by-step explanation:
First, let's find the surface area of both the triangles
5x3=15
So, the surface area of the triangles is 15 sq.cm
Now, let's find the surface area of the base (large rectangle in the middle)
12x8=?
10x8=80
2x8=16
80+16=96
12x8=96
So, the surface area of the base, is 96sq.cm
Now, let's find the surface area of both of the side rectangles
12x5=60
60x2=120
So, the surface area of the two side rectangles is 120sq.cm
Now, let's find the total surface area by adding all of our answers.
120+96=216
216+15=231
<h2>
So hence, the surface area of this net is 231cm²</h2>
Answer:
s^2
Step-by-step explanation:
Let s be the length of the side of the original square piece. The maximum circle that can be inscribed in the square has a diameter of s, or a radius of s/2. Now, to inscribe a square in this circle, its maximum dimension, the diagonal, will be equal to the diameter of the circle, s. This square will have sides of s/SQRT(2), and so have an area of s^2/2. Since the area of the original piece is s^2, exactly one half of the area has been chopped off in this rather wasteful metal shop procedure.
Answer:
-1, 0, 2
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
14. The distance between the two points is 14.866.
Distance can be calculated with the following formula:
d=√(x₂-x₁)²+(y₂-y₁)²
d=√(12-2)²+(5-(-6))²
d=√10²+11²
d=√100+121
d=√221
d=14.866
15. The distance between the two points is 20.248.
Use the same formula to find the distance.
d=√(x₂-x₁)²+(y₂-y₁)²
d=√(4-(-3))²+(12-(-7))²
d=√7²+19²
d=√49+361
d=√410
d=20.248
