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nikitadnepr [17]
4 years ago
7

How can I solve this question

Mathematics
1 answer:
Tom [10]4 years ago
4 0
V=lwh
13/2 x 3/2 x 4/2
6.5 x 1.5 x 2
19.5 but I must have done something wrong?
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Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.
Sidana [21]

Answer:

Yes

Step-by-step explanation:

rectangle a has a 2 to 3 ratio in length and width same with rectangle b

8 0
3 years ago
What is the area of the polygon given below?
Julli [10]
You didn’t add a picture !
8 0
3 years ago
Mary is driving a car of mass 900 kilograms toward the north with a velocity of 22 meters/second. Danny is driving his
Flauer [41]

Answer:

D). 2.4 x10^{4} \frac{kg*m}{s}

Step-by-step explanation:

Mary is driving toward north so the angle is 90° and Danny is driving toward the east so angle is 0°

Momentum Dary= 900 kg* 22 \frac{m}{s}

Momentum Danny= 900 kg* 15 \frac{m}{s}

So the total momentum is the magnitude:

Mag= \sqrt{(900 kg*22\frac{m}{s} )^{2}+(900kg*15\frac{m}{ys} )^{2}}

mag= \sqrt{574290000}=23.96434852 x10^{3}≅2.4 x10^{4}

4 0
4 years ago
What is the value of -7(x to the second power - 6) +2y when x=2 and y =-6
alexgriva [62]

Answer:

if x equals 2 and y equals negative 6 then the answer is....

A. -1

Step-by-step explanation:

5 0
3 years ago
Match the statements with their values.
icang [17]

Answer:

1) (B)

2) (A)

3) (D)

4) (C)

Step-by-step explanation:

Given:

There are 4 statements and we need to find the answer of each statement.

Statement 1:

m ∠ABC + m ∠BAC + m ∠ACB when Δ ABC is an isosceles triangle

Sum of all interior angles of a triangle is always equal to 180°.

⇒  m ∠ABC + m ∠BAC + m ∠ACB = 180°

Therefore, the correct option is (B).

Statement 2:

m∠ABC when m∠BAC = 70° and ΔABC is an isosceles triangle

From the triangle ABC, ∠A = 70, ∠B = ∠C(Isosceles triangle property)

Let ∠B = ∠C = 'x'.

Sum of all interior angles of a triangle is always equal to 180°.

⇒  m ∠ABC + m ∠BAC + m ∠ACB = 180°

x+70+x=180\\2x+70=180\\2x=180-70\\2x=110\\x=\frac{110}{2}=55

m ∠ABC = ∠B = 55° [Option (A)]

Statement 3:

m∠QPR when m∠QRP = 30° and ΔPQR is an isosceles triangle.

From the triangle QPR, ∠R = 30°, QP ≅ QR

Now, from isosceles triangle definition, the angles opposite to the congruent sides are also congruent. Therefore,

∠P = ∠R = 30°

Now, m∠QPR is same as ∠P. So,  m∠QPR = 30° [Option D].

Statement 4:

m∠BDE when m∠BAC = 45° and points D and E are the midpoints of AB and BC, respectively, in ΔABC

From the figure shown below,

DE is the midsegment of sides AB and BC. Therefore, from midsegment theorem, DE || AC (third side).

Therefore, for two parallel line DE and AC cut by transversal AB,

m∠BDE = m∠BAC (Corresponding angles are congruent)

m∠BDE = 45° [Option C]

5 0
3 years ago
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