4^2 equals 16. 16+25=41
The answer would be 41
Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Answer:
Step-by-step explanation:
a) <u>Jamal spent:</u>
<u>Isaiah spent:</u>
<u>The equation is:</u>
b) <u>Solving the equation</u>
- 2x = 3x - 6.75
- 3x - 2x = 6.75
- x = 6.75
c) <u>Jamal's items cost </u>
<u>Isaiah's items cost </u>
- $6.75 - $2.25 = $4.50 each