A two digit number has a tens digit and a ones digit.
Let's say x = tens digit and y = ones digit
"The sum of the digits is 5"
x + y = 5
The next phrase is "the number multiplied by 3 is 42" but we need to represent the number using the digits. So they need to be multiplied first by their place value and added together. [Example: 34 = 3(10) + 4(1)]
The number is: 10x + y
3(10x + y) = 42
The system of equations: (two equations for two unknowns)
x + y = 5
30x + 3y = 42
Then you can use substitution or elimination to combine and solve.
I'll use elimination, multiply the entire top equation by -3 and add the equations together. y will cancel out
-3x - 3y = -15
30x + 3y = 42
------------------
27x + 0 = 27
x = 1
then plug x = 1 into either equation to find y
1 + y = 5
y = 4
remember the x and y represent digits so the number xy is 14
F(2) = 3(2)^2 + 2(2) + 4
= 3(4) + 4 + 4
= 12 + 8
f(2) = 20
f(a+h) = 3(a+h)^2 + 2(a+h) + 4
= 3(a^2 + 2ah + h^2) + 2a + 2h + 4
f(a+h) = 3a^2 + 6ah + 3h^2 + 2a + 2h + 4
Answer:
11
Step-by-step explanation:
W^7/W^-2=W^7+2=W^9 ( when divide subtract the exponent (7-(-2))
W^?/W² = W^?-2
W^9=W^(?-2)
9=?-2
?=11
W^7/W^-2 = W^11/W²
Answer:
2
x + 3y − 6
Step-by-step explanation:
If you simplify you should get 2
x + 3y − 6
Answer:
x > -1
(-1, infinity)
Step-by-step explanation:
