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Sloan [31]
3 years ago
7

Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and

a standard deviation of 16 seconds. Thus, 99.7% of running times are approximately between:
A. 61 and 125 seconds

B.77 and 109 seconds

C. 45 and 141 seconds

D. None of the answer options is correct
Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

C. 45 and 141 seconds

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 93 seconds

Standard deviation = 16 seconds

99.7% of running times are approximately between:

By the Empirical rule, within 3 standard deviations of the mean, so between 3 standard deviations below the mean and 3 standard deviations above the mean

3 stnadard deviations below the mean

93 - 3*16 = 45 seconds

3 standard deviations above the mean

93 + 3*16 = 141 seconds

The correct answer is:

C. 45 and 141 seconds

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3 years ago
Four percent of Jennie's skin cells were burned when she escaped from a fire. If 3.7 x 10^10 of her skin cells were burned then,
baherus [9]

Answer:

355.2

Step-by-step explanation:

Given:

Four percent of Jennie's skin cells were burned

Total skin cells having Jennie = 3.7 x 10^10

                                                  = 3.7\times10\times10 = 370

To find:

How man skin cells were not burned ?

Solution:

Total skin cells having Jennie = 370

Percent of Jennie's skin cells were burned = 4%

Skin cells burned  from a fire = 370 \ of 4\%

                                                = 370\times\frac{4}{100} =\frac{1480}{100}

                                                = 14.8

Remaining skin cells which not burned = 370 - 14.8 = 355.2

Therefore,  355.2 skin cells were not burned.

8 0
3 years ago
A spinner has four sections lettered A, B, C, and D. The table shows the results of several spins. Find the experimental probabi
Degger [83]
Experimental probability is the outcome during a certain experiment. add up the total number of times it was spinned. You should get 40. To find the experimental probability of each section, simply divide the number by 40. This will give you the percentage for each one. For example, spinner A. 14/40=.35  Multiply this by one hundred to find the percentage (35%). Do this for all and let me know if you need help converting them to fractions. :)
5 0
3 years ago
Read 2 more answers
a store stocked 150 cans of popcorn for a weekend sale. that weekend, 72 of the can sold. what percent of the cans of popcorn st
xenn [34]

Answer:

change/original×100

72/150×100

=48%

3 0
3 years ago
The first term of a geometric sequence is 7, and the ratio (multiplier) is 3. what is the sum of the first 5 terms of the sequen
Anni [7]
Hello,

1)
a_{1}=7
a_{2}=7*3
a_{3}=7*3^2

a_{n}=7*3^{n-1}

s=a_{1}+a_{2}+a_{3}+a_{4}+a_{5}=7*(1+3^1+3^2+3^3+3^4)
=7*\frac{3^{5}-1}{3-1}
=7*242/2=847

2)
b_{8}=6*8^{8-1}=12582912




















4 0
3 years ago
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