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Irina18 [472]
3 years ago
8

40+30+45+50+23+7+15+6+4+10=?

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0

The answer is 230. Good luck

Vladimir [108]3 years ago
7 0

your answer is 230.

you just have ro add each one together

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A store charges $280 for coat. This price is 40 percent more than the amount it cost the store to buy. At the end-of-season sale
NeX [460]
Let cost price be x
according to question
x + 40% of x = 280
x+ 0.4x=280
1.4x=280
x=200
this 200 is the store cost or cost price for store
30%of 200= 60
according to question,
cost for employee= 200-60= 140
7 0
3 years ago
-1/3+4+2/3 what is the answer plz and thank you
koban [17]
Hi there!

-  \frac{1}{3}  + 4 +  \frac{2}{3}  =
First we rearrange the sum in order to add both of the fractions first. We can rearrange because the only thing we need to do is adding.

-  \frac{1}{3}  +  \frac{2}{3}  + 4 =
Add the fractions.
** If you don't get this, think of this story: you lack 1/3 of an apple pie and someone gives you 2/3 of pie. How much pie do you have left?
- 1 / 3 + 2 / 3 = 1 / 3 **

\frac{1}{3}  + 4 =
Finally add 4 to our found fraction.

\boxed{ 4\frac{1}{3} }
Therefore, the answer is 4 1/3.

5 0
3 years ago
Prove that sinxtanx=1/cosx - cosx
maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}

Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)

Therefore,

\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}

Once

\dfrac{\sin(x)}{\cos(x)} = \tan(x)

Then,

\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)

Hence, it is proved

5 0
3 years ago
If y varies inversely as x, find the constant of variation if y=36 when x=9
Jobisdone [24]

Answer:

k = 324

Step-by-step explanation:

Y varies inversely as x

Let k be the constant of variation

Y = k/ x

Y= 36 and x= 9

Substitute the value of Y and x

36 = k/9

Make k the subject of the formula

k= 36*9

k =324

5 0
3 years ago
The ratio of Isabella's money to Shane's money is 3:11. If Isabella has $33, how much money do Shane and Isabella have together?
Sergio039 [100]
The ratio of Isabella’s money to Shane’s money is 3:11

Isabella has $33.   

We can make a proportion to solve for how much money Shane has.   
A proportion is two ratios that are set equal to each other.  

Let’s call Shane’s money ‘S’   

We get this proportion:   3/11 = 33/x   

If we cross multiply we get:   
(33) * (11) = (3) * (x)   

Simplifying it, we get:
363 = (3) * (x)   

Divide both sides by 3, we get:
x = 121   

However, the question asks how much money they have together. 

Isabella + Shane = Total
33 + 121 = $154   

<span>They have $154 together.</span>
6 0
3 years ago
Read 2 more answers
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