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3 years ago

Show me work and answer for 1241 divided by 43

Mathematics

2 answers:

lbvjy [14]3 years ago

7 0

My school allows a calculator

mr_godi [17]3 years ago

4 0

The answer is 28.86046512....... rounded to the hundredth : 28.86

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Michael had $550 in his savings account. He took out $30.75 every month for one year. What is the net change in Michael’s accoun

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3 years ago

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( Write the word sentence as an equation.))) <br><br><br> 25 is 9 more than a number x.

elena-14-01-66 [18.8K]

Answer:

25>x<9

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Solve for x. write integer or simplified fraction.<br><br>22/2 = x/3

ale4655 [162]

<h3>I'll teach you how to solve 22/2 = x/3</h3>

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22/2 = x/3

Switch sides:

x/3 = 22/2

Divide the numbers 22/2:

x/3 = 11

Multiply both sides by 3:

x/3*3= 11*3

Simplify:

x=33

Your Answer Is x= 33

plz mark me as brainliest :)

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3 years ago

How did you get the answer for 0.6 for 6/10 as a terminating answer

harkovskaia [24]

When you divide 6/10 the answer is 0.6

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3 years ago

Given s left parenthesis t right parenthesis equals 5 t squared plus 5 ts(t)=5t2+5t, find

finlep [7]

Answer:

The velocity function is $v(t)=10t+5$ .

The acceleration function is $a(t)=10$ .

When t = 44, the velocity is $v(44)=445 \:\frac{ft}{s}$ .

When t = 44, the acceleration is $a(44)=10\: \frac{ft}{s^2}$ .

Step-by-step explanation:

We know that the position function is given by

$s(t)=5t^2+5t$

Velocity is defined as the rate of change of position or the rate of displacement. If you take the derivative of the position function you get the instantaneous velocity function.

$v(t)=\frac{ds}{dt}$

Acceleration is defined as the rate of change of velocity. If you take the derivative of the instantaneous velocity function you get the instantaneous acceleration function.

$a(t)=\frac{dv}{dt}$

The instantaneous velocity function is given by

$v(t)=\frac{d}{dt} s(t)=\frac{d}{dt}(5t^2+5t)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(5t^2\right)+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\v(t)=10t+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dt}\left(t\right)=1\\\\v(t)=10t+5$

The instantaneous acceleration function is given by

$a(t)=\frac{dv}{dt} =\frac{d}{dt}(10t+5)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\a(t)=\frac{d}{dt}\left(10t\right)+\frac{d}{dt}\left(5\right)\\\\a(t)=10$

To find the velocity and acceleration when t = 44, we substitute this value into the velocity and acceleration functions

$v(44)=10(44)+5\\v(44)=445 \:\frac{ft}{s}$

$a(44)=10\: \frac{ft}{s^2}$

6 0

4 years ago