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Juli2301 [7.4K]
3 years ago
12

Show me work and answer for 1241 divided by 43

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0
My school allows a calculator
mr_godi [17]3 years ago
4 0
The answer is 28.86046512....... rounded to the hundredth : 28.86
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( Write the word sentence as an equation.))) <br><br><br> 25 is 9 more than a number x.
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Solve for x. write integer or simplified fraction.<br><br>22/2 = x/3
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<h3>I'll teach you how to solve 22/2 = x/3</h3>

--------------------------------------------------

22/2 = x/3

Switch sides:

x/3 = 22/2

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3 years ago
How did you get the answer for 0.6 for 6/10 as a terminating answer
harkovskaia [24]
When you divide 6/10 the answer is 0.6
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3 years ago
Given s left parenthesis t right parenthesis equals 5 t squared plus 5 ts(t)=5t2+5t​, find
finlep [7]

Answer:

The velocity function is v(t)=10t+5.

The acceleration function is a(t)=10.

When t = 44​, the velocity is v(44)=445 \:\frac{ft}{s}.

When t = 44​, the acceleration is a(44)=10\: \frac{ft}{s^2}.

Step-by-step explanation:

We know that the position function is given by

s(t)=5t^2+5t

Velocity is defined as the rate of change of position or the rate of displacement. If you take the derivative of the position function you get the instantaneous velocity function.

v(t)=\frac{ds}{dt}

Acceleration is defined as the rate of change of velocity. If you take the derivative of the instantaneous velocity function you get the instantaneous acceleration function.

a(t)=\frac{dv}{dt}

The instantaneous velocity function is given by

v(t)=\frac{d}{dt} s(t)=\frac{d}{dt}(5t^2+5t)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(5t^2\right)+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\v(t)=10t+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dt}\left(t\right)=1\\\\v(t)=10t+5

The instantaneous acceleration function is given by

a(t)=\frac{dv}{dt} =\frac{d}{dt}(10t+5)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\a(t)=\frac{d}{dt}\left(10t\right)+\frac{d}{dt}\left(5\right)\\\\a(t)=10

To find the velocity and acceleration when t = 44, we substitute this value into the velocity and acceleration functions

v(44)=10(44)+5\\v(44)=445 \:\frac{ft}{s}

a(44)=10\: \frac{ft}{s^2}

6 0
4 years ago
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