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1 year ago

Hi, can you help me answer this question, please, thank you!

Mathematics

1 answer:

frutty [35]1 year ago

4 0

Given:

mean, u = 0

standard deviation σ = 1

Let's determine the following:

(a) Probability of an outcome that is more than -1.26.

Here, we are to find: P(x > -1.26).

Apply the formula:

$z=\frac{x^{\prime}-u}{\sigma}$

Thus, we have:

$\begin{gathered} P(x>-1.26)=\frac{-1.26-0}{1} \\ \\ P(x>-1.26)=\frac{-1.26}{1}=-1.26 \end{gathered}$

Using the standard normal table, we have:

NORMSDIST(-1.26) = 0.1038

Therefore, the probability of an outcome that is more than -1.26 is 0.1038

(b) Probability of an outcome that

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Ples help will mark brainliest if 2 answers.

BabaBlast [244]

Answer:

see below

Step-by-step explanation:

Choose a couple of values for x. Figure out the corresponding values for y. Plot those points and draw a line through them.

Let's choose x=0 and x=4. Then the corresponding y-values are ...

y = 2·0 = 0 . . . . . point (x, y) = (0, 0)

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These are graphed below.

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3 years ago

Write a rational function that meets the following criteria:

Sliva [168]

You can get a vertical asymptote at x=1 using y = 1/(x-1)
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3 years ago

Y=-1\4z+5 please grqph

svet-max [94.6K]

Answer

Attached the graph

Step by step explanation

Y = -1/4z + 5

Let's form the table values

Here z is the independent variable and y is the dependent values.

Let's take z = -1, 0, 1, 2 and find the corresponding y-values

-1 5.25

0 5

1 4.75

2 4.5

Now let's plot the points and draw the graph.

Here is the graph.

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3 years ago

Use Gauss-Jordan elimination to solve the following linear system.

marysya [2.9K]

Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]$
mulstiply 2nd row by -1 and add to 3rd
$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]$
divde last row by 2
$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]$
multiply 2rd row by 6 and add to top one
$\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]$
multiply 1st row by -1 and add to 2nd
$\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]$
divide 2nd row by -3
$\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]$
mulstiply 2nd row by -1 and add to 1st row
$\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]$
divide 1st row by -3
$\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]$

rerange
$\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]$

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer

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3 years ago

What is sin 0 when sec 0 = 5? 0 |(1,0) sin e = 2[?] [] Rationalize the denominator if necessary.

Komok [63]

Answer:

$Sin ~0 =\frac{2\sqrt{5} }{5}$