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Sedbober [7]
3 years ago
5

A researcher computes r = 0.45 using a sample of 18 participants. Is this Pearson correlation coefficient significant for a two-

tailed test at a .05 level of significance?
Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer with explanation:

Given : The computed r -value = 0.45

Sample size : n=18

Degree of freedom : df=n-2=18-2=16

Now, the critical value for Pearson correlation coefficient  for a two-tailed test at a .05 level of significance will be :

r_c=0.468   ( by critical correlation coefficient table)

Since , r>r_c i.e. 0.45>0.468 , then we say that his Pearson correlation coefficient is not significant for a two-tailed test at a .05 level of significance.

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The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos
JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the population = 500 </em>

<em>Given standard deviation of the Population = 75</em>

Let 'X' be the variable in normal distribution

      Z = \frac{x-mean}{S.D}

<em>Given X = $410</em>

<em></em>Z = \frac{410-500}{75} = - 1.2<em></em>

<u><em>Step(ii):-</em></u>

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

                  =  0.5 - A( -1.2)

                 = 0.5 - A(1.2)

                = 0.5 - 0.3849  ( ∵from normal table)

                = 0.1151

<u>Final answer:-</u>

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

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