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prohojiy [21]
3 years ago
10

Carl has two cylinders that are the same height, but the volume of the second cylinder is 36 times the volume of the first cylin

der. What is the radius of the second cylinder ?

Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0
Let radius of first cylinder is r and that of other is R and their height is h.
so vol.of first cylinder×36
=vol.of second cylinder
36×pi×r^2×h=pi×R^2×h
now pi and h cancel on both sides
so r^2×36=R^2
Squareroot36r^2=R
6r=R
so radius of second cylinder = 6 times radius of first cylinder
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I think of a number multiply it by 3 and add 6 the result is 21 what is the number
Anton [14]

Answer:

5

Step-by-step explanation:

5x3=15

15+6=21

Hope this helped pls give brainliest

4 0
3 years ago
If △NMO ∼ △XYZ, and the area of △NMO is 147 square feet, find the area of △XYZ
sladkih [1.3K]

The area of △XYZ according to the figure is 363ft²

<h3>Area of triangles</h3>

The formula for calculating the area of a triangle is expressed as:

A = 0.5bh

  • b is the base
  • h is the height

<h3>Calculate area of each triangles</h3>

For the triangle  △NMO

Area of  △NMO = 0.5bh

147 = 0.5b(14/12)

147 = 7b/12

7b = 12 * 147

b = 252

b = 252ft

b = 3024in

Get the base of △XYZ

14/3024 = 22/XZ

XZ = 4,752in

Area of △XYZ = 0.5 (4,752)(22)

Area of △XYZ= 52,272in²

Area of △XYZ = 363ft²

Hence the area of △XYZ is 363ft²

Learn more on area of triangles here: brainly.com/question/17335144

6 0
2 years ago
Which subsets of real numbers does -22 belong
deff fn [24]
Negative number because -22
3 0
3 years ago
Solve the equation 8- 2x= -8x +14
Levart [38]

Answer:

x = -1

Step-by-step explanation:

8-2x=-8x+14

8-14=-8x+2x

-6/-6=x

x=-1

4 0
2 years ago
Read 2 more answers
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
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