Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
Answer:
A= X,B
B= L,G
C= M,W
The total number of combinations is 12
Answer:
Step-by-step explanation:
hypotenuse=2*AB
where AB is the smallest side.
Take AB as the base .
Draw a perpendicular at B.
A as the center and cut an arc AC=2 AB
Join AC.
CAB is the reqd. triangle.
<h2>
The required "option B) 60°" is correct.</h2>
Step-by-step explanation:
In question figure,
∠ YUV = 40°, ∠ XUY = 105° and ∠WUX = 155°
To find, the value of ∠ VUW = ?
We know that,
The circle having 360°
∴ ∠ VUW + ∠ YUV + ∠ XUY + ∠WUX = 360°
⇒ ∠ VUW + 40° + 105°+ 155° = 360°
⇒ ∠ VUW + 300° = 360°
⇒ ∠ VUW = 360° - 300°
⇒ ∠ VUW = 60°
∴ The value of ∠ VUW = 60°
Hence, the required "option B) 60°" is correct.
This is only my opinion. I could be wrong.
My guess is:
Somebody else used that book before you, maybe last year or
the year before, and it was somebody who didn't mind writing
in his book.
One day he didn't have time to write down the homework in his
assignment notebook, so he just circled the homework problems
in his textbook.
