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3 years ago

Guys I need the answers to number 16

Mathematics

1 answer:

Umnica [9.8K]3 years ago

6 0

#16: Let's clear the fraction on the way to solving this inequality for x. By mult. the given inequality by 2, we'll get -2 (is greater than) x+4. We want x to be positive. So, leave it where it is. Subtract 4 from both sides of this inequality. We end up with -6 (is greater than) x, which is the same thing as x (is less than) -6. What would the graph of that simple inequality look like?

Graph it. (Hint: The graph is a straight dashed line, and you must shade one side of it, but not the other side.

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Classify each number as rational or irrational and explain.<br> 125<br> -0.75 v2<br> 7,548,123

emmainna [20.7K]

Answer:

Rational

125

7,548,123

Irrational

-0.75 v2

Any number (or part of a number) that contains a square root is irrational because NO square root can be expressed as a fraction. (Or a "ratio", hence the term "irRATIOnal" - meaning no ratio or no fraction)

Step-by-step explanation:

3 0

3 years ago

Inveres laplace transform (3s-14)/s^2-4s+8

Olenka [21]

Complete the square in the denominator.

$s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4$

Rewrite the given transform as

$\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}$

Now take the inverse transform:

$L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}$

5 0

3 years ago

What is the solution to the system of equations?

slamgirl [31]

Answer:

Use math slover program and you will find the answer for this questions faster.

Mark me a brainlest..

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4 years ago

Which option is correct and how would one solve for it?

Colt1911 [192]

Answer:

-3/5, -1, -5/3, -3, -7

Step-by-step explanation:

Let x go from 1 to 5

x =1 (1+2)/(1-6) = 3/-5 = -3/5

x =2 (2+2)/(2-6) = 4/-4 = -1

x =3 (3+2)/(3-6) = 5/-3 = -5/3

x =4 (4+2)/(4-6) = 6/-2 = -3

x =5 (5+2)/(5-6) = 7/-1 = -7

7 0

3 years ago

Which expressions are equavilent to 5^x

marshall27 [118]

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3 years ago